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QveST [7]
3 years ago
5

Write an integer that represents 14,000 feet below sea level

Mathematics
1 answer:
masha68 [24]3 years ago
4 0
- 14,000 feet hopefully....
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Point A has the coordinates (2,2). What are the coordinates of its image point if it is translated 2 units up and 5 units to the
Marysya12 [62]
A translation of 2 units up will increase the y coordinate by 2 units and a translation by 5 units to the left will decrease the x coordinate by 5. Hence after these translations point (2,2) becomes 

<span>(2 - 5 , 2 + 2) = (-3,4) </span>

When point (-3,4) is reflected in the x axis, its y coordinate changes sign and point (-3 ,4) becomes 

<span>(-3,-4)</span>
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3 years ago
WILL PICK BRAINLIEST!!
juin [17]
The area of the triangle is 49 in2, so she can create only 2 triangles.
7 0
3 years ago
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In triangle ABC, a = 4, b =5, angle c = 110, find length of median to the longest side
Sonbull [250]
69............................
3 0
3 years ago
Pls help if you actually can
Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A.  The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB  (Alternate Interior Angles)

∠BPE ≅ ∠BCG  (Alternate Interior Angles)

∠GBC ≅ ∠EBP  (Vertical Angles)

C.  To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375  

PE = 260 ft

BE/425 = 225/325  

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

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5 0
2 years ago
Sin(a+b).cos(a-b) = sinacosa + sinbcosb
Rainbow [258]
Sin (A + B) = sin A cos B + cos A Sin B 
<span>Cos (A - B) = cos A cos B + sin A sin B </span>

<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>

<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>

<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved 

</span>
4 0
3 years ago
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