Answer:
rise/run
Step-by-step explanation:
-5 how high/ low you go on y axis
3 how far you move left on the graph
Put in a equality
20 > (70/x)
then you solve
20x > 70
x>70/20
x> 3.5 you can not put part of a chair in a row so you round up
****You can put 4 or more chairs in a row****
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Let's solve your inequality step-by-step.
3 ≤ 7 + g
Step 1:Simplify both sides of the inequality.
3 ≤ g + 7
Step 2: Flip the equation.
g + 7 ≥ 3
Step 3: Subtract 7 from both sides.
g + 7 − 7 ≥ 3 − 7
g ≥ −4
Answer:
g ≥ −4
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Answer:
Step-by-step explanation:
Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.
The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.
The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).
The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120
(0+2)^3*(0-3)*k = 120
-24k = 120
k = -5
Combining all three conditions, f(x)
= -5(x+2)^3*(x-3)
= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)
= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)
= -5(x^4 + 3x^3 - 6x^2 - 28x -24)
= -5x^4 - 15x^3 + 30x^2 + 140x + 120
Answer: 11113200
Step-by-step explanation:
We know that , the number of combination of choosing r things from n things is given by :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-
∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200
