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melomori [17]
2 years ago
6

Conrad drew 2 angles. Three times the measure of angle 1 is 30° more than 5 times the measure of angle 2. The sum of twice the m

easure of angle 1 and twice the measure of angle 2 is 180°. Find the measure of each angle.
Mathematics
1 answer:
ad-work [718]2 years ago
3 0
Let x= measure of angle 1
Let y= measure of angle 2

This is solving a system of equations

3x=30+ 5y which can also be written

3x-5y=30, and

2x+2y=180
There are a few ways to solve this, like solving for x in one of the equations and plugging it in for x in the other equation, but here is another way:
2(3x-5y)=2*30
3(2x+2y)= 3*180

6x-10y=60
6x+6y=540, and now subtract to get rid of x
0-16y=-480
Y=30
Plug it back in to either equation and you get x=60

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2 years ago
The answer is 35 degrees, but I am unsure of the process in order to get to that answer.
hammer [34]

Answer:

Step-by-step explanation:

Hello There!

So first things first

we need to find the measure of ∠ABD

If you didn´t know the sum of the triangle angles is 180

so to find ∠ABD we subtract the given angles ( 30 and 25) from 180

180-25-30=125

so angle ∠125

Now lets find ∠DBC

∠ABD and ∠ DBC are supplementary angles so the sum of the two angles is 180

So to find ∠DBC we subtract 125 from 180

180-125=55

so ∠DBC = 55

Now we can find the measure of ∠BDC

remember like stated before the sum of all of the angles in a triangle is 180

So to find the measure of ∠BDC we subtract the given angles from 180

180-90-55=35

so we could conclude that ∠BDC = 35

Other ways to solve for ∠DBC:

angle DBC is an exterior angle of ΔABD

the measure of an exterior angle is equal to the sum of the opposite interior angles

so basically ∠DBC = ∠ADB + ∠BAD

30+25=55 so ∠DBC = 55

Other ways to find angle BDC:

Having found the measure of ∠DBA and the other opposite angle we could find ∠BDC

Like stated before the measure of an exterior angle is equal to the sum of the opposite interior angles

basically ∠DBA = ∠BDC + ∠BCA

we have the measures of ∠BCA and ∠DBA so we plug in the values

125=∠BDC+90

isolate the variable by subtracting each side by 90

125-90=35

we´re left with

∠BDC=35

I hope this helps and if you have anymore questions, feel free to ask! :)

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