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never [62]
2 years ago
11

What's the answer to this math problem? 3c+2= −10

Mathematics
2 answers:
coldgirl [10]2 years ago
3 0

3+2=−10

3c+2=-103c+2=−10

3+2−2=−10−2

3=−12

c=-4

I hope this please Mark me as brainliest ;)

viva [34]2 years ago
3 0

Answer:

c=-4

Step-by-step explanation:

3c+2=-10

3c=-12

c=-4

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In the ordered pair (2, 3), what is the x-coordinate? y-coordinate?
blagie [28]

Answer:

2 = x- coordinate

3 = y coordinate

Step-by-step explanation:

REMEMBER: In an ordered pair, the x-coordinate always comes first.

3 0
3 years ago
The longest side of a triangle is 5 in longer than the shortest side. The medium side is 4 in longer than the shortest side. If
aliina [53]

Answer: Shortest side = 6 inches, Medium side = 10 inches and Longest side = 11 inches

Step-by-step explanation: The perimeter has been given as 27 inches, and we know that the perimeter of any given figure is the addition of all sides. The sides are unknown yet, but we have clues as follows;

The longest side is 5 inches longer than the shortest side, hence the longest side equals s + 5. The medium side is 4 inches longer than the shortest side, hence the medium side equals s+ 4. Th shortest side remains s.

Therefore with the perimeter given as 27, we now have the expression;

s + s + 4 + s + 5 = 27

3s + 9 = 27

Subtract 9 from both sides of the equation

3s = 18

Divide both sides of the equation by 3

s = 6

Hence, the sides of the triangle are given as 6, (6+ 4) and (6+ 5), which is,

6 inches, 10 inches and 11 inches.

7 0
3 years ago
The range for the given domain of the function f(x)=3x-6/x+4.5 is
mash [69]
Hello,

We can not divide by 0.

==> x+4.5≠0
==>x≠-4.5

dom f=R\{4.5}
4 0
3 years ago
Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

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