All categories

3 years ago

A clock has a diameter of 8 inches. What is the circumference of this clock? u get brainlest if u answer

Mathematics

1 answer:

irga5000 [103]3 years ago

7 0

Answer:

$c=8\pi$

Step-by-step explanation:

$c = 2\pi r$

$d = 2r$

$8 = 2r\\r = 4$

Substitute in 4 for the radius

$c = 2\pi (4)\\c = 8\pi$

You might be interested in

Diego went out for a walk. He walked for 20 minutes East at a rate of 5km/hour. He then turned around and walked west for 10 min

iVinArrow [24]

Positive 20 and negative 10 is a net amount of 10. 10 minutes is 1/6 of an hour. 5*1/6=5/6km

3 0

3 years ago

Solve this equation using the radical equation method

Yuki888 [10]

The domain:
$3x+6\geq0\ \ |-6\\3x\geq-6\ \ \ |:3\\x\geq-2\\\\D:x\in\left< -2;\ \infty\right)$

$2x=\sqrt{3x+6}-1\ \ \ |+1\\\\2x+1=\sqrt{3x+6}\ \ \ \ |^2\\\\(2x+1)^2=\left(\sqrt{3x+6}\right)^2\ \ \ |use:\ (a+b)^2=a^2+2ab+b^2\\\\(2x)^2+2\cdot2x\cdot1+1^2=3x+6\\\\4x^2+4x+1=3x+6\ \ \ \ |-3x-6\\\\4x^2+x-5=0\\\\4x^2-4x+5x-5=0\\\\4x(x-1)+5(x-1)=0\\\\(x-1)(4x+5)=0\iff x-1=0\ \vee\ 4x+5=0\\\\x=1\ \vee\ 4x=-5\\\\x=1\in D\ \vee\ x=-1.25\in D$

$Answer:\ \boxed{x=-1.25\ \vee\ x=-1}$

6 0

3 years ago

What type of association would you expect to see between the amount of fog in the sky and the distance that a pilot can see? A)

Blizzard [7]

We can make a conclusion that the more fog there is, the less distance the pilot can see. this means that there is a negative association because if this were graphed, the slop would be negative, as the x-axis (amount of fog) increases and the y-axis (distance pilot can see) decreases.

7 0

3 years ago

Copy the problems onto your paper, mark the givens and prove the statements asked. Given: ∠BTO ≅ ∠IWE WI ≅ BT , OW ≅ ET Prove: △

Varvara68 [4.7K]

Answer:

$\triangle BOT \cong \triangle IEW$

Step-by-step explanation:

We are given the following in the question:

$\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW$

We have to prove:

$\triangle BOT \cong \triangle IEW$

Proof:

$\text{In }\triangle BOT \text{ and } \triangle IEW$

we can write:

$\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}$

Hence, the two triangle are congruent by SAS congruency rule.

$\triangle BOT \cong \triangle IEW$

The attached image shows the two triangle.

8 0

3 years ago

Order these objects from heaviest to lightest. (Note: 1 pound = 16 ounces, 1 kilogram ≈ 2.2 pounds ,and 1 Tom = 2,000 pounds) it

Leya [2.2K]

Answer:

Ordering of objects from heaviest to lightest are ⇒ <u> school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.</u>

Step-by-step explanation:

Given:

School bus weight = 9 tons.

Horse = 1,100 pounds.

Elephant = 5,500 kilograms.

Grand piano = 15,840 ounces.

Now, order these objects from heaviest to lightest.

So, we need to take a common unit to order the items:

Thus, we take pounds as a common unit.

16 ounces = 1 pound.

1 kilogram = 2.2 pounds.

1 ton = 2,000 pounds.

Then, we calculate the weight of all items in pounds:

School bus 9 tons $=9\times 2000=18000\ pounds.$

Horse 1100 pounds $=1100\ pounds.$

Elephant 5500 kilograms $=5500\times 2.2=12100\ pounds.$

Grand piano 15840 ounces $=15840\div 16=990\ pounds$

According to question:

Ordering from heaviest to lightest:

<em>School bus = 18000 pounds, elephant = 12100 pounds, horse = 1100 pounds and grand piano = 990 pounds.</em>

Therefore, ordering of objects from heaviest to lightest are ⇒ school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.

7 0

3 years ago