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EleoNora [17]
3 years ago
5

A clock has a diameter of 8 inches. What is the circumference of this clock? u get brainlest if u answer

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

Answer:

c=8\pi

Step-by-step explanation:

c = 2\pi r

d = 2r

8 = 2r\\r = 4

Substitute in 4 for the radius

c = 2\pi (4)\\c = 8\pi

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Andreas93 [3]

p(green) =  \frac{no \: of \: green}{total \: } \\ p =  \frac{8}{40}   \times 100\% \\ p = 20\% \\
option 2
3 0
3 years ago
Helppppppppppppppppppppppppppppp
evablogger [386]

Answer: 33

Step-by-step explanation:

(f of g)(2) = f(g(2))

g(2) = -2(2) = -4

f(-4) = (-4)^2 - 3(-4) + 5 =

16 - - 12 + 5 =

16 + 17 =

33

7 0
1 year ago
one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola
omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1.

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

x_1 + x_2 = \frac{-b}{a}

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

x_1 \cdot x_2 = \frac{c}{a}

These relations between the solutions give us a brief idea of what the solutions should be like.

6 0
4 years ago
What is the slope of the line that passes through these two points? (6,4) 10 pa
kati45 [8]

Answer:

Step-by-step explanation:

(7-4)/(-2-6)= 3/-8 = -3/8 is the slope

5 0
3 years ago
N independent random samples of 10 men and 10 women in a coed basketball league, the numbers of points scored per season are giv
faltersainse [42]

Answer:

Step-by-step explanation:

Hello!

a)

To compare both datasets I've made a box plot for them.

The yellow one belongs to the points scored by the men and the green one is for the points scored by the women.

Women: The box seems symmetrical, the median and the mean (black square) are almost the same. The whiskers are almost the same length, you could say that in general the points scored by the women have a symmetrical distribution.

Men: The box looks a little skewed to the right, the median is closer to the 1st quantile and the mean is greater than the median. The whiskers are the same length, in general the distribution seems almost symmetrical.

b)

As you can see in the box plot  the median and mean of the points scored by the women are almost the same. Using the data I've calculated both values:

Me= 24.50

X[bar]= 23.80

The median divides the sample in halves (50-50),  it shows you where the middle of the distribution is.

The average shows you the value that centers the distribution, meaning, it is the value around which you'll find most of the data set. It summarizes best the sample information and therefore is a better measure of center.

c.

As you can see in the box plots, there are no outliers in both distributions.

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.

Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:

X < Q₁ - 1.5 IQR

X > Q₃ + 1.5 IQR

Or extreme outliers if:

X < Q₁ - 3 IQR

X > Q₃ + 3 IQR

For the women data set:

Q₁= 17; Q₃= 30; IQR= 30 - 17= 13

Lower outliers: X < Q₁ - 1.5 IQR= 17-1.5*13= -2.5 ⇒ The minimum value recorded is 03, so there are no outliers.

Upper outliers: X > Q₃ + 3 IQR= 30 + 1.5*13= 49.5 ⇒ The maximum value registered is 41, so there are no outliers.

I hope this helps!

6 0
3 years ago
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