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zmey [24]
3 years ago
10

An experiment is performed in which a crystalline substance is added to a beaker filled with room temperature water. The followi

ng observations are made:
I. The crystals dissolve
II. A precipitate is formed.
III. The bottom of the beaker feels warm to the touch.
IV. Bubbles begin forming within the water. All of the observations are evidence of a chemical change EXCEPT -
A.observation I
B.observation II.
C.observation III.
D.observation IV.
Chemistry
1 answer:
Dafna1 [17]3 years ago
3 0
A i think....don't take my word for it ompletely
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.400 moles of CO2 gas are confined in a 5.00-liter container at 25 °C. Calculate the pressure exerted in atmospheres and mm Hg.
solong [7]

The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or  1486.788 mm Hg.

<h3>The ideal gas law</h3>

According to the ideal gas law, the product of the pressure and volume of a gas is a constant.

This can be mathematically expressed as:

pv = nRT

Where:

p = pressure of the gas

v = volume

n = number of moles

R = Rydberg constant (0.08206 L•atm•mol-1K)

T = temperature.

In this case:

p is what we are looking for.

v = 5.00 L

n = 0.400 moles

T = 25 + 273

 = 298 K

Now, let's make p the subject of the formula of the equation.

p = nRT/v

  = 0.400 x 0.08206 x 298/5

  = 1.9563 atm

Recall that: 1 atm = 760 mm Hg

Thus:

1.9563 atm = 1.9563 x 760 mm Hg

                   = 1486.788 mm Hg

In other words, the pressure exerted by the gas in atm is 1.9563 atm and in mm HG is 1486.788 mm Hg.

More on the ideal gas law can be found here: brainly.com/question/28257995

#SPJ1

8 0
1 year ago
Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re
laiz [17]

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.

6 0
3 years ago
A mixture that results when substances dissolve to form a homogeneous mixture
MrRa [10]
A mixture that results when substances dissolve to form a homogeneous mixture is a solution.
3 0
3 years ago
The process of splitting and Atom into two lighters atoms is called?
natima [27]
<span>The process of splitting and Atom into two lighters atoms is called </span>Nuclear Fission
5 0
4 years ago
This means that the steel bar lost 14900 J of thermal energy. What is the change in temperature of the steel bar? Recall that th
stiv31 [10]

Answer:

ΔT=-747,13°C

Explanation:

Sensible heat is<em> the amount of thermal energy that is required to change the temperature of an object</em>, the equation for calculating the heat change is  given by:

Q=msΔT

where:

  • Q, heat that has been absorbed or realeased by the substance [J]
  • m, mass of the substance [g]
  • s, specific heat capacity [J/g°C] (
  • ΔT, changes in the substance temperature [°C]

To solve the problem, we clear ΔT of the equation and then replace our data:

Q=msΔT

ΔT=Q/ms

ΔT=\frac{-14900 J}{40,7g*0,49\frac{J}{gC} }=-747,13°C

<em>(Note that Q=-14900 J because there is a </em><u><em>LOST</em></u><em> of thermal energy)</em>

Thus, the change in temperature of the steel bar is -747,13°C, meaning that the temperature of the bar decreases.

5 0
4 years ago
Read 2 more answers
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