For Any gas:
P V = n R T
where:
P : pressure
V : volume
n : number of moles
R : gas constant
T : absolute temperature in kelvin
provided that:
V = 53 LS.T.P means standard temperature and pressure at which pressure is
1 atm and temperature is
273 K
R = 0.08205 atm.L /mol.K
So:
n =
=
= 2.4 moles
The correct answer is A) 2.4
Answer: Option (A) is the correct answer.
Explanation:
Volatility is defined as the ability of a substance to readily evaporate into the atmosphere.
A small chain of hydrocarbon will have molecules in a small surface area. Moreover, a small chain hydrocarbon will have lesser dispersion forces due to which molecules are able to evaporate into the atmosphere easily.
Short carbon chain hydrocarbon will also be less viscous in nature.
Therefore, hydrocarbons consisting of short carbon chains are more volatile than hydrocarbons with longer chains.
Answer:
The sedimentary rocks includes enormous amounts of organic matter that is produced by the decomposition and degradation of the dead matter from plants and animals.
Explanation:
Answer:
Yeasts reproduce asexually by a process called budding (see Figure 8.2. 1 and Figure 8.2. 6). A bud is formed on the outer surface of the parent cell as the nucleus divides.
Explanation:
The first step in balancing any redox reaction is determining whether or not it is even an oxidation-reduction reaction, which requires that species exhibits changing oxidation statesduring the reaction. To maintain charge neutrality in the sample, the redox reaction will entail both a reduction component and an oxidation components and is often separated into independent two hypothetical <span>half-reactions </span>to aid in understanding the reaction. This requires identifying which element is oxidized and which element is reduced. For example, consider this reaction:
<span><span><span>Cu(s)+2A<span>g+</span>(aq)→C<span>u<span>2+</span></span>(aq)+2Ag(s)</span>(1)</span><span>(1)<span>Cu(s)+2A<span>g+</span>(aq)→C<span>u<span>2+</span></span>(aq)+2Ag(s)</span></span></span>
The first step in determining whether the reaction is a redox reaction is to splitting the equation into two hypothetical half-reactions. Let's start with the half-reaction involving the copper atoms:
<span><span><span>Cu(s)→C<span>u<span>2+</span></span>(aq)</span>(2a)</span><span>(2a)<span>Cu(s)→C<span>u<span>2+</span></span>(aq)</span></span></span>
The oxidation state of copper on the left side is 0 because it is an element on its own. The oxidation state of copper on the right hand side of the equation is +2. The copper in this half-reaction is oxidized as the oxidation states increases from 0 in Cu to +2 in Cu2+. Now consider the silver atoms
<span><span><span>2A<span>g+</span>(aq)→2Ag(s)</span>(2b)</span><span>(2b)<span>2A<span>g+</span>(aq)→2Ag(s)</span></span></span>
In this half-reaction, the oxidation state of silver on the left side is a +1. The oxidation state of silver on the right is 0 because it is an element on its own. Because the oxidation state of silver decreases from +1 to 0, this is the reduction half-reaction.
Consequently, this reaction is a redox reaction as both reduction and oxidation half-reactions occur (via the transfer of electrons, that are not explicitly shown in equations 2). Once confirmed, it often necessary to balance the reaction (the reaction in equation 1 is balanced already though), which can be accomplished in two ways because the reaction could take place in neutral, acidic or basic conditions.
