Answer:
a. 916.95K is final temperature of the gas
b. 3667.8K
Explanation:
a. We can solve the temperature of a gas when the volume is expanded three times using Gay-Lussac's law:
P₁T₂ = P₂T₁
<em>Where P is pressure,</em>
<em>And T is absolute temperature of 1, initial states and 2, final states of the gas.</em>
<em />
Initial pressure is 6.60 atm, initial absolute temperature is 32.5°C + 273.15K = 305.65K. Final pressure is three times initial pressure = 6.60atm*3 = 19.8atm.
Solving for final temperature:
P₁T₂ = P₂T₁
6.60atm*T₂ = 19.8atm*305.65K
T₂ =
916.95K is final temperature of the gas
<em />
b. Charle's law is the gas law that relates changes in volume and temperature of a gas:
V₁T₂ = V₂*T₁
If the volume is quadrupled: V₂/V₁ = 4:
T₂ = 4*916.95K
T₂ = 3667.8K
Answer:
362,5J
Explanation:
formula for calculating Gravitational Potential Energy is mass×gravitational field strength ×height
12.5×10×2.9=362,5J
Chlorine needs only one electron to complete valance shell and Na needs give up electron be get down to last complete valence shell. so Na+Cl
Answer: Option A) 25mL
Explanation:
Given that,
Original volume of gas (V1) = 75mL
Original temperature of gas (T1) = 450K
New volume V2 = ?
New temperature T2 = 150K
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
75mL/450K = V2/150K
To get the value of T2, cross multiply
75mL x 150K = 450K x V2
11250mL•K = 450K•V2
Divide both sides by 450K
11250mL•K / 450K = 450K•V2/450K
25mL = V2
Thus, the new volume of the gas is 25mL
Can you make the picture clearer please or tell me what I’m supposed to do in comments?