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3 years ago

What would -4/4 reduce too?

Mathematics

2 answers:

sergeinik [125]3 years ago

7 0

Answer:

-1

Step-by-step explanation:

Since 4 divided by 4 is 1 and a negative number divded by a positive number or vice versa is a negative number, the answer would be -1

Nadusha1986 [10]3 years ago

4 0

-1 is what you’d reduce it to

You might be interested in

A circle with radius \pink{9}9start color #ff00af, 9, end color #ff00af has a sector with a central angle of \purple{120^\circ}1

GrogVix [38]

Answer:

Area of sector = 84.861

Step-by-step explanation:

Given

The radius of the circle = 9

central angle of sector = $120^{o}$

value of pi π = 3.143

To find : the area of sector = ?

We know that the formula to calculate area of sector is given as:

area of sector = (π $r^{2}$ Θ)/ $360^{o}$

where, r is radius and Θ is the central angle of the sector

Substituting the known values in above formula, we get

area of sector = (3.143 x $9^{2}$ x $120^{o}$ ) / $360^{o}$

= 84.861

Hence area of sector is 84.861

3 0

4 years ago

Read 2 more answers

-2x+4=10 3/4x =2 Plz help ill give brainly

Archy [21]

Answer:

$a) \: - 2x + 4 = 10 \\ 4 = 10 + 2x \\ 4 - 10 = 2x \\ - 6 = 2x \\ \frac{ - 6}{2} = x \\ - 3 = x \: or \: x = - 3 \\ \\ b) \: \frac{3}{4x} = 2 \\ 3 = 2 \times 4x \\ 3 = 8x \\ x = \frac{3}{8} \\ 0.375 = x \: \: or \: x = 0.375$

Step-by-step explanation:

please mark me brainliest

5 0

3 years ago

Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))

BartSMP [9]

By using De Moivre's theorem:

If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ $\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )$
k= 0, 1 , 2, ..... , (n-1)

For The given complex number ⇒ z = 81(cos(3π/8) + i sin(3π/8))


Part (A) find the modulus for all of the fourth roots

∴ The modulus of the given complex number = l z l = 81

∴ The modulus of the fourth root = $\sqrt[4]{z} = \sqrt[4]{81} = 3$

Part (b) find the angle for each of the four roots

The angle of the given complex number = $\frac{3 \pi}{8}$
There is four roots and the angle between each root = $\frac{2 \pi}{4} = \frac{\pi}{2}$
The angle of the first root = $\frac{ \frac{3 \pi}{8} }{4} = \frac{3 \pi}{32}$
The angle of the second root = $\frac{3\pi}{32} + \frac{\pi}{2} = \frac{19\pi}{32}$
The angle of the third root = $\frac{19\pi}{32} + \frac{\pi}{2} = \frac{35\pi}{32}$
The angle of the fourth root = $\frac{35\pi}{32} + \frac{\pi}{2} = \frac{51\pi}{32}$

Part (C): find all of the fourth roots of this

The first root = $z_{1} = 3 ( cos \ \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})$
The second root = $z_{2} = 3 ( cos \ \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})$

The third root = $z_{3} = 3 ( cos \ \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})$
The fourth root = $z_{4} = 3 ( cos \ \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})$

7 0

4 years ago

What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?

Nadya [2.5K]

x-intercepts are found by setting y=0
$y=2x^2-8x-10\rightarrow0=2x^2-8x-10$
factor out a 2 $0=2(x^2-4x-5)\rightarrow0=x^2-4x-5$
 $0=(x-5)(x+1)$ roots should be x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)

y-intercepts are found by setting x=0
$y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10$
$\rightarrow y=0-0-10=-10$
therefore, y-intercept is (0,-10)

4 0

3 years ago

The area of a square is given by the expression s•s square inches, where s is the length of a side in inches. Write the expressi

grandymaker [24]

This can also be written as A = s^2 and the area would be 49 with a side length of 7.

In order to find this, you can stick 7 into the area equation.

A = s^2

A = 7^2

A = 49

6 0

4 years ago