In ΔBCD, the measure of ∠D=90°, BC = 81 feet, and DB = 52 feet. Find the measure of ∠C to the nearest tenth of a degree.
2 answers:
Answer:
<em>39.9° </em>
Step-by-step explanation:
m∠C = β
sin β =
⇒ β = arcsin
≈ <em>39.9°</em>
Answer:
39.9
Step-by-step explanation:
sinC=
sin C = \{52}{81}
sinC=
81
52
C=\sin^{-1}{52}{81})
C=sin −1
( 81
/52
)
C=39.9393\ 39.9^
C=39.9393≈39.9∘
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