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3 years ago

In ΔBCD, the measure of ∠D=90°, BC = 81 feet, and DB = 52 feet. Find the measure of ∠C to the nearest tenth of a degree.

Mathematics

2 answers:

kenny6666 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

m∠C = β

sin β = $\frac{52}{81}$ ⇒ β = arcsin $\frac{52}{81}$ ≈ <em>39.9°</em>

Lyrx [107]3 years ago

7 0

Answer:

39.9

Step-by-step explanation:

sinC=

sin C = \{52}{81}

sinC=

C=\sin^{-1}{52}{81})

C=sin −1 ( 81 /52 )

C=39.9393\ 39.9^

C=39.9393≈39.9∘

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