The gravitational potential energy becomes work driving the pipe
<span>m g h = f d </span>
<span>450 * g * 1.5 = f * .45</span>
Answer:
7.85 m/s^2
Explanation:
linear or tangential acceleration= dv/dt
⇒
=0.83 m/s^2
radial acceleration is given by =
⇒
= 7.81 m/s^2
total acceleration
putting values we get
= 7.85 m/s^2
Refer to the diagram shown below.
Because of symmetry, equal forces, F, exist between the sphere of mass m and each of the other two spheres.
The acceleration of the sphere with mass m will be vertical as shown.
The gravitational constant is G = 6.67408 x 10⁻¹¹ m³/(kg-s²)
Calculate F.
F = [ (6.67408 x 10⁻¹¹ m³/(kg-s²))*(m kg)*(2.8 kg)]/(1.2 m)²
= 1.2977 x 10⁻¹⁰ m N
The resultant force acting on mass m is
2Fcos(30°) = 2*(1.2977 x 10⁻¹⁰m N)*cos(30°) = 2.2477 x 10⁻¹⁰m N
If the initial acceleration of mass m is a m/s², then
(m kg)(a m/s²) = (2.2477 x 10⁻¹⁰m N)
a = 2.2477 x 10⁻¹⁰ m/s²
Answer:
The magnitude of the acceleration on mass m is 2.25 x 10⁻¹⁰ m/s².
The direction of the acceleration is on a line that joins mass m to the midpoint of the line joining the known masses.
Answer:
a). The potential is highest at the center of the sphere
Explanation:
We k ow the potential of a non conducting charged sphre of radius R at a point r < R is given by
Therefore at the center of the sphere where r = 0
Now at the surface of the sphere where r = R
Now outside the sphere where r > R, the potential is
This gives the same result as the previous one.
As
Thus, the potential of the sphere is highest at the center.
Refer to the diagram shown below.
x = the distance (horizon) that you can see from the balloon,
Because the radius of the earth is 6400 km, and the balloon is 350 n above the earth's surface, therefore
h = 6400 + 0.350 = 6400.35 km.
From the Pythagorean theorem, obtain
x = √(6400.35² - 6400²) = 66.934 km
Answer: Your horizon is 66.934 km (or 66,934 m)