Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w
1 answer:
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Answer:
= 4.86 s
= 1.98 s
Explanation:
<u><em>Given:</em></u>
Length = l = 1 m
Acceleration due to gravity of moon = = 1.67 m/s²
Acceleration due to gravity of Earth = = 10 m/s²
<u><em>Required:</em></u>
Time period = T = ?
<u><em>Formula:</em></u>
T = 2π
<u><em>Solution:</em></u>
<u>For moon</u>
<em>Putting the givens,</em>
T = 2(3.14)
T = 6.3
T = 6.3 × 0.77
T = 4.86 sec
<u>For Earth,</u>
<em>Putting the givens</em>
T = 2π
T = 2(3.14)
T = 6.3 × 0.32
T = 1.98 sec
Let be the height of the building and thus the initial height of the ball. The ball's altitude at time
is given by
where is the acceleration due to gravity.
The ball reaches the ground when after
. Solve for
:
so the building is about 16 m tall (keeping track of significant digits).