1. It’s true
4 ,7 ,8 is correct
A : Solid to liquid
Solids have a variable volume and shape before it changed. Liquids can change in shape but have a fixed volume ( ex: water holding it’s shape in the cup until the person spills it )
Answer:
"6.67 mm" is the right solution.
Explanation:
The given values are:
- L = 2.5 m
- y = .0125
- λ = 600 nm
As we know, the equation
⇒ ![\frac{y}{L} =\frac{x \lambda}{a}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7BL%7D%20%3D%5Cfrac%7Bx%20%5Clambda%7D%7Ba%7D)
On substituting the values, we get
⇒ ![\frac{.0125}{2.5}=\frac{(1)(600\times 10^{-9}) }{a}](https://tex.z-dn.net/?f=%5Cfrac%7B.0125%7D%7B2.5%7D%3D%5Cfrac%7B%281%29%28600%5Ctimes%2010%5E%7B-9%7D%29%20%7D%7Ba%7D)
On applying cross multiplication, we get
⇒ ![.0125a=2.5 (600\times 10^{-9})](https://tex.z-dn.net/?f=.0125a%3D2.5%20%28600%5Ctimes%2010%5E%7B-9%7D%29)
⇒ ![a=\frac{2.5(600\times 10^{-9})}{.0125}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2.5%28600%5Ctimes%2010%5E%7B-9%7D%29%7D%7B.0125%7D)
⇒ ![=1.2\times 10^{-4} \ m](https://tex.z-dn.net/?f=%3D1.2%5Ctimes%2010%5E%7B-4%7D%20%5C%20m)
For new distance, we have to put this value of "a" in the above equation,
⇒ ![\frac{y}{1.5} =\frac{(1)(600\times 10^{-9})}{1.2\times 10^{-4}}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B1.5%7D%20%3D%5Cfrac%7B%281%29%28600%5Ctimes%2010%5E%7B-9%7D%29%7D%7B1.2%5Ctimes%2010%5E%7B-4%7D%7D)
⇒ ![(1.2\times 10^{-4})y=1.5(600\times 10^{-9})](https://tex.z-dn.net/?f=%281.2%5Ctimes%2010%5E%7B-4%7D%29y%3D1.5%28600%5Ctimes%2010%5E%7B-9%7D%29)
⇒ ![y=\frac{1.5(600\times 10^{-9})}{1.2\times 10^{-4}}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1.5%28600%5Ctimes%2010%5E%7B-9%7D%29%7D%7B1.2%5Ctimes%2010%5E%7B-4%7D%7D)
⇒ ![=3.22\times 10^{-3} \ m](https://tex.z-dn.net/?f=%3D3.22%5Ctimes%2010%5E%7B-3%7D%20%5C%20m)
The total distance will be twice the value of "y", we get
= ![6.67\times 10^{-3} \ m](https://tex.z-dn.net/?f=6.67%5Ctimes%2010%5E%7B-3%7D%20%5C%20m)
or,
= ![6.67 \ mm](https://tex.z-dn.net/?f=6.67%20%5C%20mm)
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