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Lyrx [107]
3 years ago
5

The trace of an n×n matrix A, denoted tr(A), is thesum of its diagonal entries; that is,tr(A) = a11 + a22 +· · ·+annShow that(a)

tr(AB) = tr(BA)(b) if A is similar to B, then tr(A) = tr(B).

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer:

Step-by-step explanation:

for two matrices A, B to be Similar, then A = SBS⁻¹

A=SBS−1⟹trace(A)=trace((SB)(S−1))=trace((S−1)(SB))=trace((SS−1)B)=trace(B)

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What is the answer to this question?
levacccp [35]
Angle A of triangle ABC will be ...
  ∠A = θ₂ -θ₃ = 77° -26° = 51°
Angle B of triangle ABC will be ...
  ∠B = 180° -θ₂ -θ₁ = 180° -77° -44° = 59°
Then angle C will be ...
  ∠C = 180° -∠A -∠B = 180° -51° -59° = 70°

By the Law of Sines,
  a/sin(∠A) = c/sin(∠C)
  a = c×sin(∠A)/sin(∠C)
  a = (57 yd)×sin(51°)/sin(70°) ≈ 47.14 yd

The distance from B to C is 47.14 yd.
5 0
3 years ago
The oxygen levels in parts per million and altitude in x miles at Mt. Everest decrease according to the function: 0 (x)= 100(.95
CaHeK987 [17]

Using the exponential function, it is found that the oxygen level at 10 miles is of 59.87 ppm.

<h3>What is the exponential function for the oxygen levels?</h3>

The oxygen levels in ppm for an altitude of x miles at the Mount Everest is given by the following exponential function:

O(x) = 100(0.95)^x

In this problem, the altitude is of x = 10 miles, hence the oxygen level in ppm is of:

O(10) = 100(0.95)^{10} = 59.87

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

3 0
2 years ago
I never got this type of subject . Please help me !
Vilka [71]
F 2/5  here is the answer i am not good at working this out but i can do this in my head very easily 
7 0
3 years ago
If there was a club for 115 minutes and it starts at 10 o'clock what time will it finish?
LenaWriter [7]
115 minutes is 1 hour and 55 minutes. 1 hour and 55 minutes after 10 o'clock is 11:55. So, the club will finish at 11:55.
5 0
3 years ago
A total of 397 tickets were sold for the school play. They were either adult tickets or student tickets. There were 53 fewer stu
Arturiano [62]
We know:
397 total
53 fewer student tickets than adult tickets

Variables: A for adult tickets, S for student tickets

Known Equations:
a + s = 397
a = s + 53

Solving:
2s + 53 = 397 so 2s = 344 so s = 172

s + a = 397
172 + (172 + 53) = 397 so 172 + 225 = 397

Adult tickets sold: 225
Student tickets sold: 172


4 0
3 years ago
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