If 5% more than a is b, and b is 15% less than, what is the ratio of a to c

I need help im stuck

Katyanochek1 [597]

Answer:

4712.4

Step-by-step explanation:

I got the same question a few days ago.

The volume is πr^2 * h / 3

r = 15

h = 20

225π * 20 / 3

1500π

It's 4712.38898

Round to 4712.4

6 0

3 years ago

Help find the angle of k please

Rudiy27

Answer:

k+27=180(co-interior angle)

k=180-27=153°

7 0

3 years ago

Answer these 2 questions please

Whitepunk [10]

Hi there!

Question 1:

For this, we are taking away 1/4 yards of spring from 7/8 yards. This is essentially just subtracting 1/4 from 7/8. This then gives us the equation:

$\frac{7}{8}-\frac{1}{4}$

Now, to subtract these, we want to make it so the denominators are the same, or the numbers on the lower half are the same. (One way to explain why this is true is: $\frac{a}{b}-\frac{c}{b}=a\frac{1}{b}-c\frac{1}{b}=(a-c)\frac{1}{b}=\frac{a-c}{b}$ ). Now, to make it so the denominators are the same, we can multiply the second fraction, 1/4, by 2/2 as 2/2 is essentially 1, and multiplying by 1 will get the same result, just with a denominator switched in this case. Doing this, we get:

$\frac{7}{8}-\frac{1}{4}\cdot\frac{2}{2}$

$\frac{7}{8}-\frac{2}{8}$

Now, subtracting the numerators, we get:

$\frac{5}{8}$ yards of string will remain.

Question 2:

For this, we are combining these two thicknesses, and thus we add 1/4 to 7/12. This gives us the equation:

$\frac{1}{4}+\frac{7}{12}$

Now, we again want to make it so the denominators are the same. (Here's a similar proof but for addition this time: $\frac{a}{b}+\frac{c}{b}=a\frac{1}{b}+c\frac{1}{b}=(a+c)\frac{1}{b}=\frac{a+c}{b}$ ). Now, to make the denominators the same, we can multiply the first fraction, 1/4, by 3/3 (also equivalent to 1). Doing this, we get:

$\frac{1}{4}\cdot\frac{3}{3}+\frac{7}{12}$

$\frac{3}{12}+\frac{7}{12}$

$\frac{10}{12}$ , which is equivalent to (dividing both the top and the bottom by 2) $\frac{5}{6}$ inches.

Hope this helps!

8 0

3 years ago

The lee's spend $ 31 on movie tickets for 2 adults and 3 children. The Smith's spent $ 26 on movie tickets for 2 adults and 2 ch

Trava [24]

Answer:

Cost of adult ticket is $8 and Cost of children ticket is $5.

Step-by-step explanation:

Given:

Let the cost of each Adult ticket be 'x'.

Let the cost of each child ticket be 'y'.

Now Given:

The lee's spend $ 31 on movie tickets for 2 adults and 3 children.

Number of adult tickets = 2

Number of children ticket = 3

Total money spent = $31

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

$2x+3y=31 \ \ \ \ equation \ 1$

Also Given:

The Smith's spent $ 26 on movie tickets for 2 adults and 2 children

Number of adult tickets = 2

Number of children ticket = 2

Total money spent = $26

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

$2x+2y=26 \ \ \ \ equation \ 2$