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Viktor [21]
3 years ago
12

Please help, I really need help

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0
So the teacher bought 1/4 of the brownie pan. And it came out to $4.
 I hope this helps! :)

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Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
H U R R Y 2 0 P O I N T S
koban [17]

Distance is 26 hehhehehehehe :)

4 0
3 years ago
Please help i rlly need itttt
Olenka [21]

Answer:

The value of x is the value where the line crosses the x-axis!

________________________________________________________

Hope this helps!!

Please tell me if I have made a mistake!!

I enjoy learning from them:)

8 0
2 years ago
Read 2 more answers
Can someone help me, please ?? im stuck 
Tresset [83]

Part A

5x - 5 >= 10 or-3x + 1 > 13

1) This is a disjunction (OR)

5x - 5 >= 10

5x >= 15  

 x >= 3

or

-3x + 1 > 13

-3x > 12

  x < -4

Answer

x <- 4 or x >= 3


Part C:

1) This is a conjunction (And)

5x+ 3 <= 18 and 4 - x < 6

5x <= 15       and  - x < 2

 x <= 3    and        x > -2

Answer

-2 < x <= 3

8 0
3 years ago
Tracy is trying to justify a step in her paragraph proof. What is the property that she should use?
Kipish [7]
Symmetric property i think but i’m not sure
3 0
3 years ago
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