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3 years ago

The triangular sail on Esther's sailboat measures 10.5 feet, 14 feet and 17.5 feet on its three

Mathematics

1 answer:

pentagon [3]3 years ago

5 0

Answer:

The sail is a right triangle.

Step-by-step explanation:

We are given the following in the question.

Measure of triangular sales are:

10.5 feet, 14 feet and 17.5 feet

We have to check whether it is a right angled triangle or not.

Pythagoras theorem:

According to this theorem the sum of of squares of two sides of triangle is equal to the square of hypotenuse of triangle. The hypotenuse is the longest side of the triangle.

Verifying:

$(10.5)^2 + (14)^2\\=110.25 + 196\\=306.25\\=(17.5)^2$

Thus, the measurement of sail follows the Pythagoras theorem.

Hence, the sail is a right triangle.

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Solve the Differential equation 2(y-4x^2) dx + x dy = 0

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In a building there are 30 cylindrical pillars. The radius of each pillar is 42 m and height is 7 m. Find the total cost of pain

SashulF [63]

Answer:

The total cost of painting the curved surface area of all pillars at the rate of Rs 10 per square meter is Rs.554400.

Step-by-step explanation:

Given : In a building there are 30 cylindrical pillars. The radius of each pillar is 42 m and height is 7 m.

To find : The total cost of painting the curved surface area of all pillars at the rate of Rs 10 per square meter ?

Solution :

Radius of each pillar r= 42 m

Height of each pillar h= 7 m

The curved surface area of each pillar is $CSA=2\pi rh$

Substitute the value,

$CSA=2\times \frac{22}{7}\times 42\times 7$

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Area of 30 pillars is given by,

$A=1848\times 30=55440\ m^2$

The curved surface area of all pillars at the rate of Rs.10 per square meter.

The cost painting is $C=55440\times 10=Rs.554400$

Therefore, the total cost of painting the curved surface area of all pillars at the rate of Rs 10 per square meter is Rs.554400.

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3 years ago