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3 years ago

Any number that is divisible by 2 is also divisible by 6. Find a counterexample to show that the conjecture is false. 24 14

Mathematics

2 answers:

sdas [7]3 years ago

7 0

200 wpould be the best answer is divisible bye 2 but not 6

Elina [12.6K]3 years ago

4 0

This example is false because 10 and 14 are not divisible by 6.

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Step-by-step explanation:

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2 years ago

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3 years ago

Assume that the notation (a,r,s,t) means multiply q and r, then add the product to s and (2,6,4,8)+(4,7,2,6)? Please show work a

Mama L [17]

<h3>Answer: 7.0 (choice E)</h3>

=============================================

Work Shown:

$\perp (q,r,s,t) = \frac{qr + s}{t}\\\\\perp (2,6,4,8) = \frac{2*6 + 4}{8}\\\\\perp (2,6,4,8) = \frac{12 + 4}{8}\\\\\perp (2,6,4,8) = \frac{16}{8}\\\\\perp (2,6,4,8) = 2\\\\$

Let m = 2 so we can use this result later.

$\perp (q,r,s,t) = \frac{qr + s}{t}\\\\\perp (4,7,2,6) = \frac{4*7 + 2}{6}\\\\\perp (4,7,2,6) = \frac{28 + 2}{6}\\\\\perp (4,7,2,6) = \frac{30}{6}\\\\\perp (4,7,2,6) = 5\\\\$

Let n = 5 so we can use this result later.

Add the two results.

m+n = 2 + 5 = 7.0 is the final answer.

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1 year ago