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sergiy2304 [10]
3 years ago
12

10!•4!/6!•5! Evaluate O 1,008 O 4/3 2/3

Mathematics
2 answers:
cluponka [151]3 years ago
6 0

Answer:

1008

Step-by-step explanation:

10!•4!

---------

6!•5!

Rewriting as

10 * 9*8*7*6!  * 4!

---------

6!•5*4!

Canceling like terms

10 * 9*8*7

---------

5

1008

Luden [163]3 years ago
3 0

Answer:

1,008

Step-by-step explanation:

The answer is not 4/3 or 2/3. So, it has to be 1,008.

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<span>
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3 years ago
Question 131 ptsIt takes a team of 8 workers 2 hours and 15 minutes to clean 12 apartments. Howmany apartments can the tearsclea
Amanda [17]
48\:apartments\:in\:9\:hours

1) In this problem, the first thing to do is to enlist the categories:

workers time to clean # apartments

8 2h15 12

8 9 x

2) Note that the number of cleaners is the same. So, we can pick the ratios that fall under the category <em>time </em>and <em>#apartments</em>

<em />

We need to convert that 2h 15 into decimal form before setting the ratios:

2h15\:2+\frac{15}{60}=2.25

3) Now, we can set the ratios and solve for x:

\begin{gathered} \frac{2.25}{9}=\frac{12}{x} \\ 2.25x=12\cdot9 \\ \frac{2.25x}{2.25}=\frac{108}{2.25} \\ x=48 \end{gathered}

Thus, the answer is 48

5 0
1 year ago
MATH QUESTION PLZ HELP
umka2103 [35]
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4 0
3 years ago
Grant spent 2.50,$4.00,$4.25, and $3.25?On breakfast one week.The next week he spent $6 more in total for the 4 breakfasts than
masha68 [24]

We have been given that Grant spent $2.50, $4.00, $4.25, and $3.25 on breakfast in one week. The next week he spent $6 more in total for the 4 breakfasts than the week before. We are asked to find increase in the mean of second week.  

Since Grant spent $6 more than last week, we will divide 6 by 4 to get how much mean of second week breakfast expenditures increased with respect to first week expenditures.

\text{Mean increase in second week breakfast expenditure}=\frac{6}{4}

\text{Mean increase in second week breakfast expenditure}=1.5

Therefore, mean of second week breakfast expenditure will be $1.5 more than first week.

3 0
3 years ago
Suppose Julio is a veterinarian who is doing research into the weight of domestic cats in his city. He collects information on 1
fomenos

Answer:

Estimate of the standard error of the mean = 0.38 lb

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 10.87 lb

Sample size, n = 131

Standard deviation, σ = 4.31 lb

We have ti find the estimate of the standard error of the mean.

Formula for standard error:

S.E= \dfrac{\sigma}{\sqrt{n}}

Putting values, we get,

S.E = \dfrac{4.31}{\sqrt{131}} = 0.3766 \approx 0.38

0.38 lb is the standard error of the mean.

7 0
3 years ago
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