x - 3y = 1 ⇒ 3x - 9y = 3
3x - 5y = 11 ⇒ 3x + 5y = 11
-14y = -8
-14 -14
y = ⁴/₇
x - 3y = 1
⁴/₇ - 3y = 1
- ⁴/₇ - ⁴/₇
-3y = ³/₇
-3 -3
y = ⁻¹/₇
(x, y) = (⁴/₇, ⁻¹/₇)
Let's call the younger student's age A and the older student's age B. The teacher's age will be T.
B = 2A
T = 5B
T+5 = 5(A+5)
Simplify the last equation.
T+5 = 5A+25
T = 5A+20
Now we have two equations solved for T, so we can set them equal to each other.
5B = 5A + 20
We can plug 2A in for B
5(2A) = 5A + 20
10A = 5A + 20
5A = 20
A = 4
To find T, we plug 4 in for A in T = 5A + 20
T = 5(4) + 20
T = 40
The answer is 40 years old.
Answer:
get rickrolled
Step-by-step explanation:
Answer:
32/3 or 10.6 repeating
Step-by-step explanation:
multiply by reciprocal
6*(16/9)
96/9
simplified to 32/3
You find the answer through the Pythagorean theorem
a^2 + b^2 = c^2 a & b are the legs and c is the hypotenuse
a = 40
b = ?
c = 41
40^2 + b^2 = 41^2
1600 + b^2 = 1681
b^2 = 1681 - 1600
b^2 = 81
b = 9
the length of the other leg is 9
i hope you found this helpful!