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Firlakuza [10]
3 years ago
8

As you move up a linear demand​ curve, the price elasticity of demand in absolute value A. decreases. B. increases. C. stays the

same. D. None of the above. On the lower part of a linear demand curve below the​ midpoint, the demand is​ ________ and raising the price causes total revenue to​ _________. A. ​elastic; decrease B. ​elastic; increase C. ​inelastic; increase D. ​inelastic; decrease
Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

The answers to the questions are;

B. increases.  

C. ​inelastic; increase.

Step-by-step explanation:

The price elasticity of demand for a linear demand in absolute value curve becomes smaller and smaller as we move downwards of the curve.

When the price elasticity of demand is calculated along a linear demand curve. This is so as for each pair of points at which the price elasticity of demand is calculated, the quantity demanded and the price change are somewhat  similar, but as we move towards the top of the demand curve, the high prices and the low quantities shows the increase in demand elasticity.

Also in the inelastic region, as it can be shown by the areas of the rectangles formed by to adjacent price points, increase in price, increases the total revenue.

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I need help ASAP <br> Integrated math II
Molodets [167]

Answer:

\boxed{ \bold{ \sf{x = 16}}}

\boxed{ \bold{ \sf{m < AFD = 82}}}

Step-by-step explanation:

\sf{5x + 18 = 3x + 50}

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒\sf{5x  - 3x = 50 - 18}

Collect like terms

⇒\sf{2x = 50 - 18}

Subtract 18 from 50

⇒\sf{2x = 32}

Divide both sides of the equation by 2

⇒\sf{ \frac{2x}{2}  =  \frac{32}{2} }

Calculate

⇒\sf{x = 16}

The value of x is 16

Now, let's find value of m<AFD :

\sf{m < afd + 5x + 18 = 180} ( sum of angle in straight line )

plug the value of x

⇒\sf{m < AFD + 5 \times 16 + 18 = 180}

Multiply the numbers

⇒\sf{m < AFD + 80 + 18 = 180}

Add the numbers

⇒\sf{m < AFD + 98 = 180}

Move constant to R.H.S and change it's sign

⇒\sf{m < AFD = 180 - 98}

Subtract 98 from 180

⇒\sf{m < AFD = 82}

Value of m<AFD = 82

Hope I helped!

Best regards!!

3 0
3 years ago
An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)
erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0
3 years ago
What is 4 to the 7th power ?
bonufazy [111]
4^7=16,384 i  used a calulator

5 0
3 years ago
What is the square root of 600
dmitriy555 [2]

Answer:

24.495 if they want it as a radical, it would be positive or negative radical 600.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
MAX POINTS!!!! Please help me solve the problem in the picture and tell me what I’m doing also explain each step.
lapo4ka [179]

Answer: j=0.4

-j+0.8=-0.9j+0.76

-j+0.8+0.9j=-0.9+0.76+0.9j

-0.1j+0.8=0.76

-0.1+0.8-0.8=0.76-0.8

-0.1j=-0.04

-0.1j/-0.1=-0.04/-0.1

j=0.4

Ya have a good day.

5 0
3 years ago
Read 2 more answers
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