Question

A gas storage tank has a volume of 15 L when the temperature is 115 C and the pressure is 114 kPa. What is the new volume of the tank if the temperature drops to -8.0 C and the pressure drops to 250.0 kPa? *

Answer 1

Answer: The new volume of the tank is 4.67 L

Explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=114kPa\\V_1=15L\\T_1=115^oC=[115+273]K=388K\\P_2=250kPa\\V_2=?\\T_2=-8^oC=[-8+273]K=265K$  

Putting values in above equation, we get:  

$\frac{114kPa\times 15L}{388K}=\frac{250kPa\times V_2}{265K}\\\\V_2=\frac{114\times 15\times 265}{388\times 250}=4.67L$

Hence, the new volume of the tank is 4.67 L