Answer:
P = 2.145kPa
Explanation:
Mass = 22.1g
Molar mass of CO2 = 44g/mol
Vol = 165mL = 0.165L
T = -188°C = (-188 + 273.15)K = 85.15K
R = 8.314J/mol.K
From ideal gas equation,
PV = nRT
P = pressure of the ideal gas
V = volume the gas occupies
n = number of moles if the gas
R = ideal gas constant
T = temperature of the gas
n = number of moles
n = mass / molar mass
n = 22.1 / 44 = 0.50moles
PV = nRT
P = nRT/ V
P = (0.5 × 8.314 × 85.15) / 0.165
P = 2145.26Pa = 2.145kPa
Pressure of the gas is 2.145kPa
I think your answer will be B. 273 k
In order to calculate the final concentration of a dilution, it is important to memorise and remember the following equation:
C1V1/C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume
We are given three of the four, and we are asked to calculate the final concentration in moles, so we may substitute these given values into our equation as follows:
C1V1 = C2V2
(2.00m)(50.0 mL) = (C2)(500mL)
100 = C2(500mL)
C2 = 0.2 m
In the final step, we simply divide 100 by 500 to get our final concentration value.
Explanation:
the sum of PE and KE is mechanical energy this means energy during motion and position I think the answer is motion and stored or it may be internal
