1.1. a quadritic pattern has a second term equal to 1, a third term equal to -6 and the fifth term equal to 14 1.1.1 calculate t
1 answer:
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Answer:
OPTION D
Step-by-step explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have
Here, is the domain and
is the co-doamin.
Therefore,
Now, OPTION A:
Substitute x = 4. We get f(x) = 3 18.
So, OPTION A is rejected.
Similarly, OPTION B:
Substitute x = 4. We get f(4) = 22 18.
It is rejected as well.
Now, for OPTION C:
Substitute x = 4. We get f(4) = -3 18.
So, OPTION C is also rejected.
OPTION D:
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>Thus the cost of children’s ticket is $ 5