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3 years ago

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1.1. a quadritic pattern has a second term equal to 1, a third term equal to -6 and the fifth term equal to 14 1.1.1 calculate t

he second difference of the quadratic pattern 1.1.2 hence or otherwise calculate the first term of the pattern

1 answer:

Allushta [10]3 years ago

6 0

Answer:

South Africa ro Duma nga mapiano

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Inga [223]

Answer:

38°

Step-by-step explanation:

The measure of required angle can be obtained by using cosine law.

From the given triangle we find that:

a = 5, b = 3, c = 7,

Since,

cos (A) = (b^2 +c^2 - a^2) /2bc

Therefore,

cos (A) = (3^2 + 7^2 - 5^2) /(2*3*7)

cos (A) = (9 + 49 - 25) /(42)

cos (A) = (33) /(42)

cos (A) = 0.785714286

A = arccos(0.785714286)

A = 38.213210675°

A = 38°

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Step-by-step explanation:

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2 years ago

Explain the steps needed to solve the inequality. <br><br> -3x + 4 > 25

r-ruslan [8.4K]

Step-by-step explanation:

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3 years ago

Three vertices of parallelogram WZXY are W(-5, 2), X(2, 4) and Z(-7, -3). Find the coordinated of the vertex, Y.

Dominik [7]

Answer:

$Y = (4,9)$

Step-by-step explanation:

Given

$W(x_1,y_1) = (-5, 2)$

$Z(x_4,y_4) = (-7, -3)$

$X(x_2,y_2) = (2, 4)$

Required

Find Y

To do this, we make use of the mid-point formula

i.e.

$M = \frac{1}{2}(x_n+x_m,y_n+y_m})$

WX and ZY are the diagonals of the parallelogram.

The mid-point of WX is:

$M = \frac{1}{2}(-5+2,2+4)$

$M = \frac{1}{2}(-3,6)$

The mid-point of ZY is:

$M = \frac{1}{2}(-7+x,-3+y)$

Equate both values of M

$\frac{1}{2}(-3,6) = \frac{1}{2}(-7+x,-3+y)$

Multiply both sides by 2

$(-3,6) = (-7+x,-3+y)$

By comparison:

$-7 + x = -3$

$-3 + y = 6$

$-7 + x = -3$

$x = 7 -3$

$x = 4$

$-3 + y = 6$

$y = 6 +3$

$y = 9$

Hence:

$Y = (4,9)$

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