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Oxana [17]
3 years ago
6

Four times a number is equal to five times the same number plus five. What is the number?

Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

Five times a number plus four times the same number is equal to 360. The number is 40. 5n + 4n = 360; 9n = 360; n = 360/9; n = 40

Step-by-step explanation:

You might be interested in
El triángulo ABC es equilátero y L, M y N son los puntos medios de BC, AB y CA respectivamente. Si MN = 3, ¿cuál es el valor de
Flauer [41]

The value of <u>ML = 3</u>, using the mid-point theorem of triangles.

According to the midpoint theorem, "the line segment of a triangle crossing the midpoints of two sides of the triangle is said to be parallel to its third side and also half the length of the third side."

In the question, we are given that triangle ABC is an equilateral triangle, and L, M, and N are the midpoints of BC, AB, and CA respectively.

Thus, by the midpoint theorem, we can say that:

  • MN || BC, and MN = (1/2)BC,
  • ML || AC, and ML = (1/2)AC, and
  • NL || AB, and NL = (1/2)AB.

Assuming AB = BC = AC = x units, we get:

  • MN = (1/2)BC = x/2,
  • ML = (1/2)AC = x/2, and
  • NL = (1/2)AB = x/2.


Thus, the triangle LMN is an equilateral triangle.

Thus, MN = ML = NL.

Given MN = 3, we can write the value of ML = 3.

Thus, the value of <u>ML = 3</u>, using the mid-point theorem of triangles.

Learn more about the mid-point theorem of triangle at

brainly.com/question/9635025

#SPJ1

The given question is in Spanish. The question in English is:

"Triangle ABC is equilateral and L, M, and N are the midpoints of BC, AB, and CA respectively. If MN = 3, what is the value of ML?"

4 0
2 years ago
(18 + 4i) + (-11 + 23i) =<br> Express your answer in the form (a + bi).
Andru [333]

Answer:

7+27i

Step-by-step explanation:

(18+4i)+(-11+23i)

=18+4i-11+23i

=7+27i

8 0
3 years ago
Solve x^2=2x+3 by factoring
solong [7]

The solution is x = 1 and x = -3

<em><u>Solution:</u></em>

Given that we have to solve the given equation by factoring

Given equation is:

x^2=2x + 3\\\\x^2 - 2x - 3 = 0

\text{Consider the form } x^2+bx+c

Find a pair of integers whose product is c and and whose sum is b

\text{Compare } x^2-2x-3 = 0 \text{ with } x^2+bx +c\\\\\text{We get } b = -2 \text{ and } c = -3

Now find, a pair of integers whose sum is -2 and product is -3

The integers that satisfies this condition is -1 and 3

When we add - 1 and 3 we get 2

When multiply -1 and 3 we get -3

Thus the pair of integers are -1 and 3

Write the factored form using these integers.

(x-1)(x+3) = 0

The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0

Set the factors equal to 0

x - 1 = 0 \text{ and } x + 3 = 0

x = 1 and x = -3

Thus the solution is x = 1 and x = -3

4 0
3 years ago
HURRY PLEASEEEEE I RLLY NEED THIS
ira [324]

Answer:table 1 would be y=x-3 and table 2 is y=x-5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need help with these 2 questions
tensa zangetsu [6.8K]
Number 1 would the last option, but I’m not sure about number 2
7 0
3 years ago
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