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Natalija [7]
4 years ago
13

Charge is distributed uniformly on the surface of a spherical balloon (an insulator). A point particle with charge q is inside.

The electrical force on the particle is greatest when: a. it is near the inside surface of the balloon b. it is at the center of the balloonc. it is halfway between the balloon center and the inside surfaced. it is anywhere inside (the force is same everywhere and Is not zero)e. it is anywhere inside (the force is zero everywhere)
Physics
1 answer:
AnnZ [28]4 years ago
3 0

Answer:

e. it is anywhere inside (the force is zero everywhere)

Explanation:

The relation between the force and electric field is given as follows

\vec{F} = \vec{E}q

where q is the charge inside, and E is the electric field inside the balloon created by the charge on the surface.

By Gauss' Law, the electric field inside the balloon created by the charges on the surface (excluding the charge q, since the electric field of the same charge cannot apply a force on the same charge) is zero.

\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E4\pi r^2 = 0\\E = 0

Since the external electric field inside the sphere is zero, then the force on the point charge is zero everywhere.

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In a Rutherford scattering experiment, an alpha particle is accelerated toward a stationary silver nucleus. If the closest appro
lys-0071 [83]

Answer:

Initial Kinetic energy of alpha particle is  9.45x10⁻¹³ J .

Explanation:

The distance at which the initial kinetic energy of the particle is equal to the potential energy is known as closest distance. As it is Rutherford scattering, so it is a coulomb potential energy.

Let K be the initial kinetic energy of alpha particle and r be the closest approach distance. So,

Initial Kinetic Energy = Coulomb Potential Energy

K = \frac{k\times2e\times{Ze}}{r }

Here, k is constant, e is charge of electron and Z is the atomic number of silver.

Put 9x10⁹ N m²/C² for k, 1.6x10⁻¹⁹ C for e, 47 for Z and 22.9x10⁻¹⁵ m for r in the above equation.

K = \frac{9\times10^{9}\times{1.6}\times10^{-19}\times{1.6}\times10^{-19}\times2\times47}{22.9\times10^{-15} }

K = 9.45x10⁻¹³ J

3 0
4 years ago
If your front lawn is 16.016.0 feet wide and 20.020.0 feet long, and each square foot of lawn accumulates 13501350 new snowflake
asambeis [7]

Answer:

The mass of snow accumulated in the lawn in 1 hour equals 57.024 kilograms

Explanation:

Given

Width of lawn = 16 feet

Length of lawn = 20 feet

Thus total area of lawn equals 16\times 20=320sq.feet\

Now it is given that 1 square foot accumulates 1350 new snowflakes each minute thus number of snowflakes accumulated by 320 square feet in 1 minute equals

320\times 1350=432000

Now it is given that average mass of each snowflake is 2.20mg=2.20\times 10^{-3}g=2.20\times 10^{-6}kg

Hence the mass accumulated per minute equals 432000\times 2.20\times 10^{-6}=0.9504kg

Now since there are 60 minutes in 1 hour thus the mass accumulated in 1 hour equals 0.9504kg\times 60=57.024kg

4 0
3 years ago
Why is nitrogen or helium filled in a filament lamp??
nirvana33 [79]
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7 0
3 years ago
g (15 points) Picture taken from problem 13-35. A 2000 kg truck is traveling at 25 meters/second. The driver suddenly hits the b
otez555 [7]

Answer:

Δx = 3.99 m

Explanation:

To determine distance, use kinetic energy

will make it short and easy.  

KE=1/2mv2 and KE=Δxmgμ

 

Set the equations equal to each other

1/2mv2=Δxmgμ            (Note: The masses cancel )

 1/2v2=Δxgμ                  Solve for Δx

where g=9.8  

Δx=v2/(2gμ)                   Δx = 25 / (2 * 9.8 * 0.32)     Δx = 3.99 m

Please let me know if its correct, if not report it so we can correct it.

6 0
4 years ago
Could I get some help with this
nika2105 [10]

please give me brainlest!!

the answer is A.

4 0
3 years ago
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