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3 years ago

An object accelerates from rest with a constant acceleration of 7.5 m/s2. How fast will it

Physics

1 answer:

Serhud [2]3 years ago

8 0

Answer:

13.4 m/s

Explanation:

Given:

Δx = 12 m

v₀ = 0 m/s

a = 7.5 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (7.5 m/s²) (12 m)

v ≈ 13.4 m/s

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Electrical power is transmitted from power plants to consumers–sometimes over very long distances– through conducting power line

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There is more wire to travel through,farther distance, and a higher possibility of other disruptions. Please Mark Brainliest!!!

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3 years ago

9. What is the gravitational potential energy of a 61.2 kg person standing on the roof of a 10-storey building? (Each storey is

kow [346]

Answer:

15009

Explanation:

PE = mgh

PE = 61.2(9.81)(10 * 2.50)

PE = 15009.3

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2 years ago

Hypothetically speaking, if an object were located at the center of the Earth, the gravitational force on that object due to the

Likurg_2 [28]

Answer:

D. ) The force would be zero newtons

Explanation:

Because

If you are at the center of the earth, gravity is zero because all the mass around you is pulling "up" (every direction there is up!)

So F=mg so if g is zero F is also zero

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3 years ago

A heat engine accepts 200,000 Btu of heat from a source at 1500 R and rejects 100,000 Btu of heat to a sink at 600 R. Calculate

diamong [38]

To solve the problem it is necessary to apply the concepts related to the conservation of energy through the heat transferred and the work done, as well as through the calculation of entropy due to heat and temperatra.

By definition we know that the change in entropy is given by

$\Delta S = \frac{Q}{T}$

Where,

Q = Heat transfer

T = Temperature

On the other hand we know that by conserving energy the work done in a system is equal to the change in heat transferred, that is

$W = Q_{source}-Q_{sink}$

According to the data given we have to,

$Q_{source} = 200000Btu$

$T_{source} = 1500R$

$Q_{sink} = 100000Btu$

$T_{sink} = 600R$

PART A) The total change in entropy, would be given by the changes that exist in the source and sink, that is

$\Delta S_{sink} = \frac{Q_{sink}}{T_{sink}}$

$\Delta S_{sink} = \frac{100000}{600}$

$\Delta S_{sink} = 166.67Btu/R$

On the other hand,

$\Delta S_{source} = \frac{Q_{source}}{T_{source}}$

$\Delta S_{source} = \frac{-200000}{1500}$

$\Delta S_{source} = -133.33Btu/R$

The total change of entropy would be,

$S = \Delta S_{source}+\Delta S_{sink}$

$S = -133.33+166.67$

$S = 33.34Btu/R$

Since $S\neq 0$ the heat engine is not reversible.

PART B)

Work done by heat engine is given by

$W=Q_{source}-Q_{sink}$

$W = 200000-100000$

$W = 100000 Btu$

Therefore the work in the system is 100000Btu

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3 years ago

At the circus, the Human Cannonball is

svlad2 [7]

The correct answer is 1.4285714.

In physics, velocity is characterised as a vector measurement of the motion's direction and speed. To be more precise, the rate of change in an object's position relative to a frame of reference and time is another way to describe velocity. The definition of velocity simply states the rate of motion of an object in a specific direction. It determines how quickly or slowly something is going.

Velocity = distance/ time

Thus time = distance/velocity

Here velocity = 350m/s

diatnce = 500 m

time = 500/350

time = 1.42857142857

t= 200m /350m/s = 1.4285714

To learn more about velocity refer the link:

brainly.com/question/18084516

#SPJ9

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1 year ago