All categories

3 years ago

Help please I need the name of the polygon and the perimeter and area of the shape of numbers 42-47

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

8 0

42 - 47

Polygons are

triangle, trapezoid, triangle, parallelogram, rectangle and parallelogram

The area of triangles = 1/2 * base * haight.

Area of the parallelograms = height * base.

Area of rectangle= width * length

Area of trapezoid = 1/2 * (a + b) * height where a and b are the opposite parallel sides

The perimeters = sum of the sides of the polygons.

You might be interested in

Jacob buys for muffins for $5 what is the cost of 7 muffins

Lyrx [107]

Answer:

35$

Step-by-step explanation:

If one muffin is 5 dollars and you buy 7 then just multiple them and get 5x7=35

8 0

3 years ago

Read 2 more answers

Maria borrowed $120,000 from a bank when she bought her co-op for $156,000.

ANTONII [103]

Answer:

hello there im sam and im going to help you with your answer.

Step-by-step explanation:

so you take the 156,000 and subtract it to 120,000 and you will get 36,000 and thats how much she owes the bank.

6 0

2 years ago

-2(6+s) Greater than or equal to -15 - 2s

Eddi Din [679]

Answer:

I'm leaning mostly towards C Because there is a solution, None of them are real numbers and if they were, S would = 5 Especially positive S

~ Zachary

7 0

3 years ago

What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4

Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

$I = \frac{P}{4\pi d^{2}}$

where P: is the power ans d: is the distance.

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

$\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}$

where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km

$\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}$

$\frac{I_{1}}{I_{2}} = 5.9:1$

Therefore, the ratio of the intensities is roughly 6:1.

I hope it helps you!

3 0

3 years ago

What is the value of x in the figure? Enter your answer in the box

Tcecarenko [31]

Answer:

x =68

Step-by-step explanation:

We know that x+22 = 90 because the sum of the two angles is a vertical angle to the right angle and vertical angles are equal.

x+22 =90

Subtract 22 from each side

x+22-22 = 90-22

x =68

3 0

3 years ago