Answer:
Step-by-step explanation:
Given
maximum
minimum
Required
Solve graphically
First, we need to determine the inequalities of the system.
For number of coins, we have:
because the number of coins is not less than 20
For the worth of coins, we have:
because the worth of coins is not more than 0.80
So, we have the following equations:
Make y the subject in both cases:
Divide through by 0.01
The resulting inequalities are:
The two inequalities are plotted on the graph as shown in the attachment.
--- Blue
--- Green
Point A on the attachment are possible solutions
At A:
Answer:
30 each of 23% bars and 18 each of 79% bars
Step-by-step explanation:
If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:
x + y = 48
0.23x + 0.79y = 0.44(48)
Substituting and solving:
0.23x + 0.79(48-x) = 0.44(48)
0.23x + 37.92 - 0.79x = 21.12
16.8 = 0.56x
x = 30
y = 48 - x
y = 18
You need 30 each of 23% bars and 18 each of 79% bars.
In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m
11 over 13 I think is the answer
Answer:
b
Step-by-step explanation:
ive done this beffore im a pro
