Answer: 1/5 or 0.2
Step-by-step explanation:
STEP 1⇒1 1/5 = 1 · 5 + 1/5 = 5 + 1/5 = 6/5
STEP 2⇒6/5 - 2/5 = 6 - 2/5 = 4/5
STEP 3⇒4/5(-3/4) = 4 ·(-3)/5 · 4 = -12/20 = -3/4
STEP 4⇒-3/5 · 3 = -3 · 3/5 · 1 = -9/5
STEP 5⇒-9/5 ÷ (-9) = -9 · 1/5 · 9 = 9/45 = 1/5
You get the hypothenuse by doing √a²+b² = c
So....
Square both terms
x² + (3x+3)² = 625
x² + 9x² + 18x + 9 - 625 = 0
10x² + 18x - 616 = 0
x₁,₂ = (-b±√Δ)/2a
Δ = b²-4ac
You call a 10, b 18 and c -616
x1,2 = (-18±√18²-4*10*-616)/2*10
x1,2 = (-18±√324+24640)/20
x1,2 = (-18±√24964)/20
x1,2 = (-18<span>±158)/20
x1 = -18+158/20 = 140/20 = 7
x2 = (-18-158)/20 = -176/20 = -44/5
Pick the first solution
So one leg is 7 and the other is 3(7+1) = 3(8) = 24
Let's verify </span>√24²+7² = √576+49 = √625 = 25
Answer:
8x⁴ - 7x³ + 12x
Step-by-step explanation:
=(4x⁴ + 7x + 5x³) + (8x⁴ + 6x³ - 3x)- (4x⁴ + 4x³ - 8x)
=4x⁴ + 7x + 5x³ + 8x⁴ + 6x³ - 3x - 4x⁴ - 4x³ + 8x
=4x⁴ + 8x⁴ - 4x⁴+ <em>5x³ + 6x³ - 4x³</em> + <u>7x - 3x + 8x</u>
=8x⁴ + 7x³ + 12x
Let point Q = (4,y)
√[ (4-0)^2 + (y-0)^2 ] = √[ (6-0)^2 + (0-0)^2 ]
Square both side
(4-0)^2 + (y-0)^2 = (6-0)^2 + (0-0)^2
4^2 + y^2 = 6^2
16 + y^2 = 36
y^2 = 36-16
y^2 = 20
y= √20
y= 2√5
Actually there are two avoidable risks here: 1) overeating and 2) smoking.