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puteri [66]
2 years ago
8

If DCAE is a parallelogram, what is the perimeter of triangle DBE?

Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

∆DBE ≅ ∆ABC by SAA

by puthagorean

BC² = AC² - AB²

BC = 4

hence, the perimeter is

3 + 4 + 5 = 12

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You begin a hike in Death Valley, California, at an elevation of -86 meters. You hike to a point of elevation at 45 meters. What
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Answer:

131

Step-by-step explanation:

(-)86+45

86 + 45 = 131

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3 years ago
he section of paper shown in the pattern below is 1/4 of a circle. It will be wrapped around a cone. The wrapper will then be pa
uranmaximum [27]

The volume of the cone based on the figure illustrated wil be 196cm³.

<h3>Host illustrate the information?</h3>

The information is incomplete and the complete question wast found online. An overview will be given.

Let's assume that the height is 4cm and the radius of the cone is 7cm. The volume of the cone will be:

= 1/3πr²h

= 1/3 × 3.14 × 7² × 4

= 196cm³

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2 years ago
What is the probability that the system does not have a type 2defect?b.What is the probability that the system has both type 1 a
Lana71 [14]

Answer:

a.  0.93 b. 0.06 c. 0.05

Step-by-step explanation:

Probability is commonly known as the chance of success of a particular event. The probability of failure of the event can also be estimated.

(a) Probability of not having type 2 defect is: P(A_{2}^{'})  = 1 - P(A_{2}) = 1 - 0.07 = 0.93

(b) Probability of having type 1 and 2 defects is: P(A_{1} n A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1}U A_{2}) = 0.12 + 0.07 - 0.13 = 0.06

(c) probability pf having both type 1 and type 2 defects but not type 3 defect is:

P(A_{1} + A_{2} + A^{'} _{3}) = P(A_{1} n A_{2}) - P(A_{1} n A_{2} n A_{3}) = 0.06 - 0.01 = 0.05

3 0
2 years ago
If the parent function is \root(3)(x), describe the translation of the function y=\root(3)(x+4)-3
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The parent function moves 4 units right and 3 units down. This is a translation by the vector.

According to the question,

Transformation \sqrt[3]{x} maps  onto \sqrt[3]{x+4} -3 . Take f(x) =  \sqrt[3]{x} and f(x+4)=\sqrt[3]{x+4}.

f(x) =  \sqrt[3]{x}

f(x+4)=\sqrt[3]{x+4}

f(x+4) - 3=\sqrt[3]{x+4} - 3

Analyze the function to see the translations. f(x-4) corresponds to a horizontal translation 4 units in the positive 'x' direction. f(x)-3 corresponds to a vertical translation 3 units in the negative 'y' direction.

Hence, the parent function moves 4 units right and 3 units down. This is a translation by the vector.

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7 0
2 years ago
im just bored this is a very easy question so i got like nothing to do rn 2+3+8= first one get brianiliest
pav-90 [236]

Answer:

Step-by-step explanation:

6 0
2 years ago
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