Answer:
i think probably 80°
Step-by-step explanation:
PQ = RS
2x+3 = 4x-3
x = 3
PTQ = RTS
9y-3x-1 = 5x+7y-5
2y-8x = -4
y-4x = -2
y-4(3) = -2
y-12 = -2
y = -2+12
y = 10
so PTQ = 9y-3x-1
9(10)-3(3)-1
90-9-1
80°
Answer:
Step-by-step explanation:
$7.45 = 100g
x = 3kg( 3 × 1000) = 3000g
∵ $7.45 = 100g
x = 3000g
(100 × x) = (7.45 × 3000)
100x = 22350
100x/100 = 22350/100
x = $223.5
Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
So I’m only answering so I can ask you a question
It would be replaced with f(-2) which is the reciperacle of 2x