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MAVERICK [17]
3 years ago
15

A sample of gas in a closed container at a temperature of 76°c and a pressure of 5.0 atm is heated to 399°c. What pressure does

the gas exert at the higher temperature?
Chemistry
1 answer:
NikAS [45]3 years ago
6 0

<u>Answer:</u> The pressure that the gas exert at high temperature is 9.63 atm

<u>Explanation:</u>

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=5.0atm\\T_1=76^oC=[76+273]K=349K\\P_2=?\\T_2=399^oC=[273+399]K=672K

Putting values in above equation, we get:

\frac{5.0atm}{349K}=\frac{P_2}{672K}\\\\P_2=9.63atm

Hence, the pressure that the gas exert at high temperature is 9.63 atm

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Explanation:

To obtain the velocity of an ideal gas you must use the formula:

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Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio is:

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<em />

I hope it helps!

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