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vladimir1956 [14]
4 years ago
14

A culinary club earns $1350 from a dinner service. They sold 35 adult meals and 58 student meals. An adult meal costs $12 more t

han a student meal.
Mathematics
1 answer:
liq [111]4 years ago
7 0
The adult meal is $38.57 and the student meal is $26.27. You can try it out on a calculator, all you have to do is divide $1350 by 35 and then subtract your answer by 12!

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What is the perimeter of ABC with vertices at A (-11,4) B(-7,8) and C (-4,4)
Alborosie

Answer:

Step-by-step explanation:

Using the distance formula,

AB=\sqrt{(-11-(-7))^{2}+(4-8)^{2}}=\sqrt{16+16}=4\sqrt{2}\\AC=\sqrt{(-11-(-4))^{2}+(4-4)^{2}}=7\\BC=\sqrt{(-7-(-5))^{2}+(8-4)^{2}}=\sqrt{4+16}=2\sqrt{5}\\\\

So the perimeter is 4\sqrt{2}+7+2\sqrt{5}

3 0
2 years ago
What is the sample space for each one of the following statements? (7.5 points each)
photoshop1234 [79]

We can define the sample space for a given experiment as the set of all the possible outcomes for the experiment.

For example, tossing a coin has a space sample of 2 elements, tails and heads.

The spaces are:

a) {WW, BB, WBB, BWW, WBWW, BWBB,... }

b) { 1-2-3-4, 1-2-3-5,..., 7-6-5-4,...}

a) We can write one element in this sample space as:

WBB

This would mean that first we draw a white ball, then a black ball, and then the second black ball, thus we stop drawing.

<u>So all the elements in this set will have the form</u>

{WW, BB, WBB, BWW, WBWW, BWBB,... }

As we have infinite balls in the bag, we have infinite elements in this set.

b) Now we have only 10 balls numbered from 1 to 10, and we draw 4.

So each element in the sample space can be written as:

1-2-3-4

This element means:

"first we draw ball number 1, then ball number 2, then ball number 3, then ball number 4"

Then the sample space will have the form:

{ 1-2-3-4, 1-2-3-5,..., 7-6-5-4,...}

If you want to learn more, you can read:

brainly.com/question/23125812

6 0
3 years ago
Help i would be very grateful
lana [24]

Answer:

4.8

Step-by-step explanation:

All you have to do is do 20% of 24.

8 0
3 years ago
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Determine which equation is parallel to the line JK and which is perpendicular to like JK
sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and y = - \frac{1}{m}x + b will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as  

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be  

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation  

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ n = - \frac{1}{m}

Therefore, the equation of a straight line which is perpendicular to equation (1) will be y = - \frac{1}{m}x + b where b is any real constant. (Answer)

3 0
4 years ago
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2/5 simply to a decimal
Nadusha1986 [10]
Your answer is 0.40 ......................
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3 years ago
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