A small airplane used 5 2/3 gallons of fuel to fly 2 hour trip. How many gallons were used each hour

Mathematics

1 answer:

kogti [31]2 years ago

5 0

5 2/3 / 2 = 17/3 * 1/2 = 17/6 = 2 5/6 gallons per hour

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For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction:

$\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}$

To find the resultant bearing (theta), we can use the formula below:

$\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}$

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

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1 year ago

Solve for x.

riadik2000 [5.3K]

I got a different answer..
and i don't see it as one of your choices, also your question is confusing since you're repeating it .-.
But anyways i got $\frac{6}{11} ~or~ \frac{36}{66}$

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3 years ago

Mmunity/classes/5d62d69dab3b9d01c471275e/assignments/ea5fbdc266ba4fb6b42ef10035395865/content/33670082-1319-3919-b805-037d3a9e87

soldier1979 [14.2K]

Answer: 8%

Step-by-step explanation:

the answer is 7.5% but you said its a whole number so i guess its 8%

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2 years ago

Which is a true stament?

solong [7]

2nd one: 2 rectangles can have thr same area but have different perimeters.