The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18
when n=4
a4=-54
when n=5
a5=-162
when n=6
a6=-486
when n=7
a7=-1458
when n=8
a8=-4374
thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560
For A B and C, you just plug in the given number
A
B
C
And for D, you set the equation to 26 and solve for n
I had to use x instead of n, but for D n=7. :)
Answer: a) No Solution
b) Infinite Solutions (All Real Numbers)
<u>Step-by-step explanation:</u>
4(g + 8) = 7 + 4g
4g + 32 = 7 + 4g <em>distributed 4 into g + 8</em>
32 = 7 <em> subtracted 4g from both sides</em>
Since the statement is false because 32 ≠ 7, then there is NO SOLUTION
-4(-5h - 4) = 2(10h + 8)
20h + 16 = 20h + 16 <em>distributed</em>
16 = 16 <em>subtracted 20h from both sides</em>
Since the statement is true because 16 = 16, then there are INFINITE SOLUTIONS so x can be all real numbers.
It is C. r=6
3 * 6 = 18 + 2 =20
