How many rays can you name using the points shown?
1 answer:
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Answer:
Out of 450 phones 18 of them will have a defect.
Step-by-step explanation:
As we know that out of 75 phones 3 of them will have a defect, this means that we are able to calculate how many defects there will be from 450 phones. You can do this by first dividing 450 by 75, this gives you 6. This means that 75 will go into 450 6 times.
From this we are able to work out the number that will have defects. This is because we know that 75 goes into 450 6 times and that for each 75 phones there will be 3 defects. So to work out the number of phones out of 450 that would be defects you would simply multiply 3 by 6, this gives you 18. This shows that out of 450 phones 18 of them will have a defect.
1) Divide 450 by 75.
2) Multiply 6 by 3.
Answer:
19 square units
Step-by-step explanation:
Hello!
Step 1: Plot the points
We are first going to plot the points on the coordinate graph and connect the points to create a shape.
Refer to attachment titled "Step 1"
Step 2: Box the shape
Since this is an irregular shape, I'm going to make a box around the shape and subtract the area of the empty spaces to find the area of the original polygon.
Refer to attachment titled "Step 2"
Step 3: Area of Edges
We are going to find the area of the shapes A, B, and C and subtract them from the area of the big box to find the area of the polygon.
Area of a triangle = 1/2(base x height)
- Area of Box = 6 un x 7 un
- Area of Box = 42 un²
Area of A:
- Area A = 1/2(4 un x 2 un)
- Area A = 1/2(8 un²)
- Area A = 4 un²
Area of B:
- Area B = 4 un x 4 un
- Area B = 16 un²
Area of C:
- Area C = 1/2(2 un x 3 un)
- Area C = 1/2(6 un²)
- Area C = 3 un²
Step 4: Area of the polygon
Now, we can simply subtract the values of A, B, and C from the box to get the area of the polygon.
- Area Polygon = Box - A - B - C
- Area Polygon = 42 un² - 4 un² - 16 un² - 3 un²
- Area Polygon = 38 un² - 16 un² - 3 un²
- Area Polygon = 22 un² - 3 un²
- Area Polygon = 19 un²
The area of the polygon is 19 un²
-Chetan K
