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3 years ago

A boat floats up and down with the time period of two seconds as the wave passes under it. What is the frequency ?

Physics

1 answer:

wolverine [178]3 years ago

3 0

A). It takes 2 seconds to happen one time.
So it happens 1/2 of a time per second.
That's a frequency of 1/2 Hertz.

b). Wave speed = (frequency) x (wavelength)

= (0.5 Hz) x (6 meters)

= 3 meters/sec

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Nitric acid (HNO3) and potassium hydroxide (KOH) combine in a neutralization reaction to form water and a salt. Which of the fol

mrs_skeptik [129]

Answer:

The answer to your question is KNO₃

Explanation:

Data

HNO₃

KOH

neutralization reaction

Process

1.- In a neutralization reaction an acid reacts with an alkali and the products are water and a binary or ternary salt.

Reactants acid = HNO₃ alkali = KOH

A neutralization reaction is a double displacement reaction so the salt formed is.

HNO₃ + KOH ⇒ H₂O + KNO₃

Potassium nitrate

5 0

3 years ago

Read 2 more answers

if 162.4 j of heat are added to a gas contained within a cylinder and the gas expands, doing 87.3 j of work, what is the change

labwork [276]

The changes in internal energy of the system 75.1 J.

The internal energy of a thermodynamic system is the total energy contained in it. It is the energy required to create or prepare a system in a given internal state and includes contributions of potential energy and internal kinetic energy.

Calculation:

Internal energy = 162.4 j - work done

= 162.4 j - 87.3 j

= 75.1 J

Internal energy, in thermodynamics, is the property or state function that defines the energy of matter in the absence of capillary action or external electric, magnetic, or other fields.

Internal energy is the microscopic energy contained in the matter given by the random and disordered kinetic energy of the molecules. It also includes the potential energy between these molecules and the nuclear energy contained in the atoms of these molecules.

Learn more about internal energy here:-brainly.com/question/15735187

#SPJ4

6 0

1 year ago

A steady beam of alpha particles (q = + 2e, mass m = 6.68 × 10-27 kg) traveling with constant kinetic energy 22 MeV carries a cu

cluponka [151]

Answer:

Explanation:

q = 2e = 3.2 x 10^-19 C

mass, m = 6.68 x 10^-27 kg

Kinetic energy, K = 22 MeV

Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A

(a) time, t = 2.8 s

Let N be the alpha particles strike the surface.

N x 2e = q

N x 3.2 x 10^-19 = i t

N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8

N = 2.36 x 10^12

(b) Length, L = 16 cm = 0.16 m

Let N be the alpha particles

K = 0.5 x mv²

22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²

v² = 1.054 x 10^15

v = 3.25 x 10^7 m/s

So, N x 2e = i x t

N x 2e = i x L / v

N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)

N = 4153.85

Kinetic energy = Potential energy

K = q x V

22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V

V = 1.17 x 10^7 V

5 0

4 years ago

Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the

Assoli18 [71]

Answer:

Part a)

$\rho = 3\epsilon_0 k r^2$

Part b)

$Q = 4\pi \epsilon_0kR^5$

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

$E = kr^3 \hat r$

now electric flux through a spherical surface of radius r is given as

$\phi = E. A$

$\phi = kr^3(4\pi r^2)$

now by Guass law we know that

$E.A = \frac{q}{\epsilon_0}$

$q = 4\pi \epsilon_0kr^5$

now volume charge density is given as

$\rho = \frac{q}{\frac{4}{3}\pi r^3}$

$\rho = 3\epsilon_0 k r^2$

Part b)

Total charge inside the radius R is given as

$Q = 4\pi \epsilon_0kR^5$

7 0

3 years ago

A watt is a unit of light power force motion energy

Crazy boy [7]

The answer would be Power

3 0

3 years ago