Ask question

Ask question

All categories

andrew-mc [135]

4 years ago

8

Get it right and win a brilliant

1 answer:

BlackZzzverrR [31]4 years ago

3 0

In Newton's third law, the action and reaction forces D.)act on different objects

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force on object B (action force), then action B exerts an equal and opposite force (reaction force) on object A"</em>

It is important to note from the statement above that the action force and the reaction force always act on different objects. Let's take an example: a man pushing a box. We have:

Action force: the force applied by the man on the box, forward
Reaction force: the force applied by the box on the man, backward

As we can see from this example, the action force is applied on the box, while the reaction force is applied on the man: this means that the two forces do not act on the same object. This implies that whenever we draw the free-body diagram of the forces acting on an object, the action and reaction forces never appear in the same diagram, since they act on different objects.

Learn more about Newton's third law of motion:

brainly.com/question/11411375

#LearnwithBrainly

You might be interested in

A bullet with a mass of 14.5 is shot out of a rifle that has a length 1.08. The bullet spends 0.14 on the barreL. What is the ac

Over [174]

Answer:

110 m/s²

Explanation:

Given:

v₀ = 0 m/s

Δx = 1.08 m

t = 0.14 s

Find: a

Δx = v₀ t + ½ at²

1.08 m = (0 m/s) (0.14 s) + ½ a (0.14 s)²

a = 110 m/s²

7 0

2 years ago

Un auto se mueve con velocidad constante de 20 m/s y la mantiene durante 20 s. Después se le aplica una aceleración constante y

pentagon [3]

Answer:

26.67 s

Explanation:

v = Velocidad final = 40 m/s

u = Velocidad inicial = 20 m/s

$t_1$ = Tiempo inicial = 20 s

$t_2$ = Tiempo empleado durante la aceleración

a = Aceleración

s = Desplazamiento del automóvil durante la aceleración = 200 m

De las ecuaciones lineales de movimiento tenemos

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{40^2-20^2}{2\times 200}\\\Rightarrow a=3\ \text{m/s}^2$

$v=u+at_2\\\Rightarrow t_2=\dfrac{v-u}{a}\\\Rightarrow t_2=\dfrac{40-20}{3}\\\Rightarrow t_2=6.67\ \text{s}$

El tiempo necesario para acelerar es 6.67 s

El tiempo total necesario para toda la ruta es $t=t_1+t_2=20+6.67=26.67\ \text{s}$ .

4 0

3 years ago

Conditional waves contain a crest, trough, wavelength, and amplitude<br> True or False?

AveGali [126]

Answer:

True

Explanation:

8 0

3 years ago

Two identical loudspeakers are driven in phase by the same amplifier. The speakers are positioned a distance of 3.2 m apart. A p

serg [7]

Answer:

f = 735 Hz

Explanation:

given,

Person distance from speakers

r₁ = 4.1 m r₂ = 4.8 m

Path difference

d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m

For destructive interference

$d = \dfrac{n\lambda}{2}$

where, n = 1, 3,5..

we know, λ = v/f

$d = \dfrac{n v}{2f}$

v is the speed of the sound = 343 m/s

f is the frequency

$f = \dfrac{n v}{2d}$

for n = 1

$f = \dfrac{343}{2\times 0.7}$

f = 245 Hz

for n = 3

$f = \dfrac{3\times 343}{2\times 0.7}$

f = 735 Hz

Hence,the second lowest frequency of the destructive interference is 735 Hz.

7 0

4 years ago

The mass of an object can change if

Serhud [2]

D. none of the above

8 0

3 years ago

Read 2 more answers