Responder:
6.704 m / s
Explicación:
Se dice que el trabajo se realiza cuando la fuerza aplicada a un objeto hace que el objeto se mueva. Primero necesitamos calcular la distancia recorrida por el perro usando la fórmula del trabajo realizado.
Trabajo realizado = Fuerza × distancia
Distancia = Trabajo realizado / Fuerza
Distancia = W / mg
S = 176/8 × 9,81
S = 176 / 78,48
S = 2,24 m
Dada la velocidad inicial u = 3.6km / h
Convertir a m / s
= 3.6km × 1000m / 1h × 3600
= 3600/3600
= 1 m / s
u = 1 m / s
Usando la ecuación de movimiento
v² = u² + 2gS para obtener la velocidad final v:
v² = 1² + 2 (9,81) (2,24)
v² = 1 + 43,9488
v² = 44,9488
v = √44,9488
v = 6,704 m / s
Por tanto, la rapidez final del perro es de 6,704 m / s
The length of the inclined plane is approximately 12 ft
The situation forms a right angle triangle.
<h3>Right triangle</h3>
Right triangle have one of its angle as 90 degrees.
Therefore,
The length of the inclined plane is the hypotenuse of the triangle. The length of the inclined plane can be found using trigonometric ratios.
height = 4 ft
angle(∅) = 19.45°
sin 19.45 = 4 / h
h = 4 / 0.33298412235
h = 12.0125847796
h = 12 ft
Therefore, the length of the inclined plane is approximately 12 ft
learn more on inclined plane:brainly.com/question/14163589?referrer=searchResults
a. 0.5 T
- The amplitude A of a simple harmonic motion is the maximum displacement of the system with respect to the equilibrium position
- The period T is the time the system takes to complete one oscillation
During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.
So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

and solving for t we find

b. 1.25T
Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that
- the mass takes a time of 1 T to cover a distance of 4A
we can set the following proportion:

And by solving for t, we find
