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2 years ago

Steve sells half of his comic books and then buys 6 more now he has 14 comic books

Mathematics

2 answers:

ddd [48]2 years ago

4 0

Let b be the initial amount of books. Steve sells half of his books, so the number of Steve's books become

$b \to \dfrac{b}{2}$

Then, he buys 6 more, so the number increases by 6:

$\dfrac{b}{2} \to \dfrac{b}{2}+6$

This number is now 14, so you have

$\dfrac{b}{2}+6 = 14$

Subtract 6 from both sides:

$\dfrac{b}{2} = 8$

Multiply both sides by 2:

$b = 16$

CaHeK987 [17]2 years ago

4 0

c/2+6=14

Subtract 6 from both sides.

c/2=8

Multiply both sides by 2.

c=16

Check your work by plugging 16 into the equation.

16/2+6=14

8+6=14

That's correct, 8+6 is 14, so the answer is that C (the number of comic books) is 16.

Steve started with 16 comic books.

I believe that's the answer to the question you meant to ask. But just to recap, the question I answered would be "How many comic books did Steve have at first?" or "How many comic books did Steve start out with?" or something similar. I hope that this answer helps!

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Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

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$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

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3 years ago

Read 2 more answers

A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.

denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let $\mu$ = population mean light bulb life.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 500 hours {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, $H_A$ : $\mu$ < 500 hours {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean bulb life = 490 hours

σ = population standard deviation = 50 hours

n = sample of light bulbs = 100

So, the test statistics = $\frac{490-500}{\frac{50}{\sqrt{100} } }$

= -2

The value of z test statistics is -2.

Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

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Answer:

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Step-by-step explanation:

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