Question

Steve sells half of his comic books and then buys 6 more now he has 14 comic books

Answer 1

Let b be the initial amount of books. Steve sells half of his books, so the number of Steve's books become

$b \to \dfrac{b}{2}$

Then, he buys 6 more, so the number increases by 6:

$\dfrac{b}{2} \to \dfrac{b}{2}+6$

This number is now 14, so you have

$\dfrac{b}{2}+6 = 14$

Subtract 6 from both sides:

$\dfrac{b}{2} = 8$

Multiply both sides by 2:

$b = 16$

Answer 2

c/2+6=14

Subtract 6 from both sides.

c/2=8

Multiply both sides by 2.

c=16

Check your work by plugging 16 into the equation.

16/2+6=14

8+6=14

That's correct, 8+6 is 14, so the answer is that C (the number of comic books) is 16.

Steve started with 16 comic books.

I believe that's the answer to the question you meant to ask. But just to recap, the question I answered would be "How many comic books did Steve have at first?" or "How many comic books did Steve start out with?" or something similar. I hope that this answer helps!