Question

Find an equation of the line that passes through the points (- 4, 3) and (4, - 3) both slope-intercept form and standard form

Answer 1

Answer:

y = $-\frac{3}{4}$ x + 0 (Slope-intercept)         3x + 4y = 0 (standard)

Step-by-step explanation:

find slope first

(-3 - 3)/(4- -4) = -6/8 = -3/4

y=mx + b

3 = -3/4 (-4) + b,    b = 0

y = -3/4x + 0, you don't have to have the + 0

multiply by 4 and add 3x to both sides.

3x + 4y = 0