Answer:
The current inside the MRI solenoid is 2387 A.
Explanation:
Given;
number of turns, N = 400
radius of the loop, r = 0.66 m
magnetic field, B = 1.2 T
The magnetic field strength inside MRI Solenoid is given by;
B = Nμ₀I
Where;
I is the current needed in the loop
Therefore, the current inside the MRI solenoid is 2387 A.
The only vertical forces acting on the wall are the weights of the man and the ladder as well as the normal force because the wall has no friction.
The maximal frictional forces are μsN2=(0.40)(900N)=360N, and N1=w1+wm=160N+740N=900N for the vertical forces to balance. At a height of 4.0 meters above the ground, the ladder makes contact with the wall. about the point of contact with the ground, balancing torques.
N2 = 174.0N because (4.0m)2 = (1.5m)(160N) + (1.0m)(35)(740N) =684N.m. It is necessary for the frictional force to counteract this horizontal force. Setting the frictional fore and n1 to a maximum of 360N and solving for the distance x along the ladder (0.4m)(360N)=(1.50m)(160N)+x(35)(740N) yields x=2.70m
<h3>Friction</h3>
When two sliding solid surfaces, fluid layers, or material components come into contact with one another, friction acts as a force to stop them from moving in the same direction. Friction comes in several forms:
The relative lateral motion of two solid surfaces in contact is opposed by dry friction. Between moving surfaces, there is kinetic friction, which is different from static friction. With the exception of atomic or molecule friction, asperities on the surface interact to produce dry friction.
When layers of a viscous fluid move in relation to one another, there is friction between them. This is known as fluid friction.
When a lubricant fluid separates two solid surfaces, it is called lubricated friction.
Learn more about friction here:
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