What is the chemical formula for copper (I) sulfide? A) CuS B) CuS2 C) Cu2S D) Cu2S3
2 answers:
This problem can be solved by using oxidation states. The oxidation state is based on the electrons an atom loses or gain, or appears to use when forming compounds.To find the formula for Copper (I) Sulfide, we have to first consider the individual ions that come together to form it. Copper (I) is an ion of copper that has a charge of +1, i.e . Sulfur is an element in group 6 of the periodic table. The sulfur ion has a charge of -2, i.e
. To form Copper (I) Sulfide, which is electrically neutral, we need 2 Copper (I) ions and 1 sulfur ion.
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The reaction is represented by the equation below
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The correct answer is (C)
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Answer:
Explanation:
The football players collide in a completely inelastic collision, in other words they have the same velocity after the collision, this velocity has a magnitude V=1.6m/s.
We need to use the conservation of momentum Law, the total momentum is the same before and after the collision, at the initial point the receiver does not have any speed
(1)
We solve in order to find the receiver mass:
Answer:
a) t = 746 s
b) t = 666 s
Explanation:
a)
- Total time will be the sum of the partial times between stations plus the time stopped at the stations.
- Due to the distance between stations is the same, and the time between stations must be the same (Because the train starts from rest in each station) we can find total time, finding the time for any of the distance between two stations, and then multiply it times the number of distances.
- At any station, the train starts from rest, and then accelerates at 1.1m/s2 till it reaches to a speed of 95 km/h.
- In order to simplify things, let's first to convert this speed from km/h to m/s, as follows:
- Applying the definition of acceleration, we can find the time traveled by the train before reaching to this speed, as follows:
- Next, we can find the distance traveled during this time, assuming that the acceleration is constant, using the following kinematic equation:
- In the same way, we can find the time needed to reach to a complete stop at the next station, applying the definition of acceleration, as follows:
- We can find the distance traveled while the train was decelerating as follows:
- Finally, we need to know the time traveled at constant speed.
- So, we need to find first the distance traveled at the constant speed of 26.4m/s.
- This distance is just the total distance between stations (3.0 km) minus the distance used for acceleration (x₁) and the distance for deceleration (x₃), as follows:
- x₂ = L - (x₁+x₃) = 3000 m - (316.8 m + 158.4 m) = 2525 m (6)
- The time traveled at constant speed (t₂), can be found from the definition of average velocity, as follows:
- Total time between two stations is simply the sum of the three times we have just found:
- t = t₁ +t₂+t₃ = 24 s + 95.6 s + 12 s = 131.6 s (8)
- Due to we have six stations (including those at the ends) the total time traveled while the train was moving, is just t times 5, as follows:
- tm = t*5 = 131.6 * 5 = 658.2 s (9)
- Since we know that the train was stopped at each intermediate station for 22s, and we have 4 intermediate stops, we need to add to total time 22s * 4 = 88 s, as follows:
- Ttotal = tm + 88 s = 658.2 s + 88 s = 746 s (10)
b)
- Using all the same premises that for a) we know that the only difference, in order to find the time between stations, will be due to the time traveled at constant speed, because the distance traveled at a constant speed will be different.
- Since t₁ and t₃ will be the same, x₁ and x₃, will be the same too.
- We can find the distance traveled at constant speed, rewriting (6) as follows:
- x₂ = L - (x₁+x₃) = 5000 m - (316.8 m + 158.4 m) = 4525 m (11)
- The time traveled at constant speed (t₂), can be found from the definition of average velocity, as follows:
- Total time between two stations is simply the sum of the three times we have just found:
- t = t₁ +t₂+t₃ = 24 s + 171.4 s + 12 s = 207.4 s (13)
- Due to we have four stations (including those at the ends) the total time traveled while the train was moving, is just t times 3, as follows:
- tm = t*3 = 207.4 * 3 = 622.2 s (14)
- Since we know that the train was stopped at each intermediate station for 22s, and we have 2 intermediate stops, we need to add to total time 22s * 2 = 44 s, as follows:
- Ttotal = tm + 44 s = 622.2 s + 44 s = 666 s (15)