0 = 4y^3 -12y^2 -40y
0 = (4y^2 -12y -40)y
0 = (4y^2 + 8 y -20y -40) y
0 = ((4y - 20) (y+2))y
y=0 \/ y= 5 \/ y= -2
Answer:
A. Third period
Step-by-step explanation:
- hope this helped!
b
the issue will be for 4/5