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vovikov84 [41]
3 years ago
14

PLEASE HELP0 = 4y^3 -12y^2 -40y

Mathematics
1 answer:
Bond [772]3 years ago
5 0

0 = 4y^3 -12y^2 -40y

0 = (4y^2 -12y -40)y

0 = (4y^2 + 8 y -20y -40) y

0 = ((4y - 20) (y+2))y

y=0 \/ y= 5 \/ y= -2

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