Answer:
The greatest number of flowers that could be in a bouquet is 9 flowers
Step-by-step explanation:
We solve the above question using Greatest Common Factor method. We find the factors of 27, 9 and 18. The greatest factor common to the 3 number is our answer.
The factors of 9 are: 1, 3, 9
The factors of 18 are: 1, 2, 3, 6, 9, 18
The factors of 27 are: 1, 3, 9, 27
Then the greatest common factor is 9.
The greatest number of flowers that could be in a bouquet is 9 flowers
Answer:
£30
Step-by-step explanation:
Let Brian initially had money in his wallet = £x
and Colin had the money = £y
Since ratio of money in Brian's wallet to Colin's wallet was 5 : 1
Therefore,
⇒ x = 5y -------(1)
Brian spent £27 that day, so money left with him = £(x - 27)
After spending the money Brian had £3 less than Colin.
(x - 27) = (y - 3)
x = y + 27 - 3
x = y + 24 -------(2)
Now we equate the equations (1) and (2) for the value of x,
5y = y + 24
5y - y = 24
4y = 24
y = £6
From equation (2),
x = 6 + 24
x = £30
Therefore, Brian initially had £30.
i hope this helps
Answer: The mean is 50.42. The Median is 40. The mode is 95
Step-by-step explanation:
She now has 6 oz. if that’s what you’re asking. If not please clarify
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
