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irina [24]
3 years ago
11

What is the area and permater of a squre whose side is 3x plus 5

Mathematics
1 answer:
deff fn [24]3 years ago
3 0
Area= height x length
        = (3x+5)²
        = 9x²+30x+25

Perimeter= All sides added together
                = 4 (3x+5)
                = 12x + 20

Hope this helps!
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The perimeter of a rectangle is (10x2).if it's width is (2x-1),which expression represents the length
alexandr402 [8]

Answer: b. 3x + 2

Step-by-step explanation:

2l + 2w = p

2l + 2(2x - 1) = 10x + 2

2l + 4x - 2 = 10x + 2

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4 0
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Paul [167]
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5 0
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Can you help with this is it right or wrong
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Answer: Yes, its right.

Step-by-step explanation:

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2 years ago
Graph F(x)=32x+2. Please
olga2289 [7]

Answer:

The required graph is shown below:

Step-by-step explanation:

Consider the provided graph f(x)=32x+2

The above function is a linear function.

We can draw the graph of the linear function with the help of two points.

Substitute x = 0 in f(x)=32x+2

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Hence, the coordinates are (0,2)

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Now join the above points.

The required graph is shown below:

5 0
3 years ago
Read 2 more answers
Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?
steposvetlana [31]

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices P(-2, 6), \ Q(-8, 4), and\  R(1, -2). It is translated according to the rule    (x, y)\ -> \  (x\  - \ 2, y\  - 16). What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is (x, y)\  -> (x - 2, \ y -16).

Now calculated the vertices P value according to the rule of translated

P(-2, 6)\\Now \  apply \ the\ translated\ rule \ in\  P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)

So -10 is the value of y in P vertices .

6 0
3 years ago
Read 2 more answers
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