Given:
mass = 6 kg
velocity = 4 m/s
To find:
Kinetic energy of the cart = ?
Formula used:
Kinetic energy = 
Where m = mass of the cart
v = velocity with which the cart is moving
Solution:
Kinetic energy of the moving cart is given by,
Kinetic energy =
Where m = mass of the cart
v = velocity with which the cart is moving
Kinetic energy =
Kinetic energy = 48 Joule
Thus, the kinetic energy of the moving cart is 48 Joule.
<span>If the reactants and the products are in a closed container and at equilibrium, so think of "trapping"</span>
ANSWER:
1. Cardiovascular Fitness
2. Muscular Fitness
3. Flexibility
4. Motivation
5. Money
6.
7. Family Behaviors
8. Understanding
is there another option for number 6? i could only find 7 word options
Answer:
1.5x10^-4C
C=Couloumb's
Explanation:
Expression for the electric force between the two charges is given by -
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
F=25N
q1 = 1.9x10^-6 x 10^-6 C
q2 = ?
r = 0.32m
Substitute the given values in the above expression -
25N= 9x10^9 *1.9x10^-6 *q2 / 0.32m^2
25N= 17,100*q2 / 0.1024m
Next part is algebra multiply both sides by 0.1024 to remove denominator
2.56=17,100*q2
Divide both sides to isolate q2
q2= 1.5x10^-4C
Answer: 477W
Explanation:
Given the following :
Mass (m) = 7.3kg
Initial Velocity (u) = 0
Final velocity (v) = 14m/s
time (t) = 1.5s
Power = workdone (W) / time (t)
The workdone can be calculated as the change in kinetic energy (KE) :
Recall ;
KE = 0.5mv^2
Therefore, change in KE is given by:
0.5mv^2 - 0.5mu^2
Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)
Change in KE = 715.4J
Therefore ;
Average power = Workdone / time
Workdone = change in KE = 715.4N
Average power = 715.4 / 1.5
Average power = 476.93333 W
= 477W
