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Pani-rosa [81]
2 years ago
13

I will mark brainliest!! The Moon travels around the Earth each month in an elliptical path, as opposed to a perfect circle.

Physics
1 answer:
Natasha_Volkova [10]2 years ago
5 0

Answer:

The magnitude decreases

Explanation:

You might be interested in
A student who was training for a cross country race jogged for 2. 0 hours and covered a distance of 14. 0 kilometers. What was t
FinnZ [79.3K]

The average speed is 116.66m/s.

Given - The path traced is 14km , time for jogging is 2 hrs=120min

To find the average speed-

  1. Speed refers to the ease of the movement and degree of mobility as a result of force application.
  2. Due to this there is involvement of velocity.
  3. Journey of average speed is the cumulative of distances and time.
  4. Kinetic theory refers to the Boltzmann constant connecting to the standards of distance traversed.

calculations-

Speed= \frac{Distance}{Time}

Speed= 14 000 / 120

= 116.66m/s

To learn more about average speed -

<u>brainly.com/question/27753148</u>

#SPJ4

6 0
1 year ago
Explain whether demand is likely to be elastic or inelastic for Big Macs. A. Elastic comma since many other fast food items coul
anyanavicka [17]

Answer:

A - elastic since many other fast food items could be considered close substitutes.

Explanation:

The price elasticity of demand is how much the demand of the Big Macs will change due to a 1% change in price. Should the elasticity be greater than 1, the Big Macs will be elastic. Should it be less than 1, the Big Macs are inelastic.  

Demand elasticity is calculated as the percentage change in quantity demanded divided by a percentage change in price.

Since Big Macs are (i) a luxury good, and (ii) have close substitutes (other burgers available at McDonalds and other fast food stores), we will say their elasticity is greater than 1.  

This means that the demand of Big Macs will change due to a 1% increase in price due to the presence of close substitutes.  

3 0
2 years ago
Two circles are drawn in a 12-inch by 14-inch rectangle. Each circle has a diameter of 6 inches. If the circles do not extend be
Dennis_Churaev [7]

Answer:

d = 10 inch

Explanation:

The farthest distance between the centers, is along the diagonal of the rectangle. Therefore, we need to calculate the diagonal of the rectangle, but counting the fact that we have both circles.

So if, one side is 12 inch, and the other is 14 inch, we can use the Pitagoras theorem which is:

d = √(a²) + (b)²

Where a and b, are the lenght of the rectangle, but without the lenght  of the diameter of both circles.

With this, the expression is this:

d = √(14 - 6)² + (12 - 6)²

d = √64+36

d = √100

d = 10 inches

6 0
3 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 2.20 kg , up an incline of constant slope an
a_sh-v [17]

Answer:

The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.

Explanation:

It is given that,

Mass of the box, m = 2.2 kg

The box is inclined at an angle of 30 degrees

Vertical distance, d = 3.1 m

The coefficient of friction, \mu=6\times 10^{-2}

Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.

KE=PE+W

\dfrac{1}{2}mv^2=mgh+W

W is the work done by the friction.

W=f\times d

f=\mu mg\ cos\theta

W=\mu mg\ cos\theta\times \dfrac{d}{sin\theta}

W=\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}mv^2=mgh+\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}v^2=gh+\dfrac{\mu gh}{tan\theta}

\dfrac{1}{2}v^2=9.8\times 3.1+\dfrac{6\times 10^{-2}\times 9.8\times 3.1}{tan(30)}

v = 8.19 m/s

So, the speed of the box is 8.19 m/s. Hence, this is the required solution.

8 0
2 years ago
A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragste
dezoksy [38]
You start by writing down your parameters;
u=60m/s
v=0
t=8s
So acceleration(a)=v-u/t
=0-60/8
=-60/8
=-7.5m/s
To the nearest hundredth will be
-7.5*100
=-750m/s
8 0
2 years ago
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