Question

A property contained ten acres. How many lots of not less than 50 feet by 100 feet can be subdivided from the property if 26,000 square feet were dedicated for roads?

Answer 1

Answer:

81 lots of 5,000 square feet fits in the property.

Step-by-step explanation:

The first step is calculate the square feet of the minimum area:

$50 \: feets \times 100 \: feet = 5,000 \:square \: feet$

Second, from the ten acres we subtract the 26,000 feets of roads:

$1 \: acre = 60 \: feet \times 660\:feet = 43,560\:square\:feet\\43,560 \times 10 = 435,600\\435,600 - 26,000 = 409,600 \:square \: feet\:available$

Third, we divide the lot area over the available square feet

$\frac{409,600}{5,000} = 81.92$

81 lots of 5,000 square feet fits in the property.