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3 years ago

What is the equation of the line that passes through the point (-8,0)and has a slope of -1/4

Mathematics

1 answer:

Dahasolnce [82]3 years ago

8 0

Answer:

y = -1/4x - 2

Step-by-step explanation:

I'm going to write this equation in slope intercept form, which looks like this: y = mx + b. First, write the equation using the slope given. It should look like this:

y = -1/4x + b

Next, you must find the y intercept by plugging in the point to the equation. This is what it looks like: 0 = -1/4(-8) + b. Multiply -1/4 by -8 to get 2. This is what your equation should look like now: 0 = 2 + b. Subtract 2 from both sides of the equation to get -2 = b. Go back to your original equation and plug -2 in for b. This is your final equation:

y = -1/4x - 2

Hope this helped!

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3 years ago

R^3 +4r^2-25r-100<br><br> Help

Marina86 [1]

Answer:

The zeroes in this equation are -5, -4, and 5

Step-by-step explanation:

In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.

r^3 + 4r^2

r^2(r + 4)

Now the second half.

-25r - 100

-25(r + 4)

Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.

(r^2 - 25)(r + 4)

And we can further factor the first parenthesis using the difference of two squares

(r^2 - 25)(r + 4)

(r + 5)(r - 5)(r + 4)

Now that we are fully factored, set each parenthesis equal to 0 and solve for x.

r + 5 = 0

r = -5

r - 5 = 0

r = 5

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3 years ago

How do you write an equation of a line given y-intercept -8 and slope 3/4

Lostsunrise [7]

Answer:

$y = \frac{3}{4} x-8$

Step-by-step explanation:

You can us the equation y = m x + c to answer this question.

In ,

y = m x + c

m = slope

c = y - intercept

So, they have already given in the question that,

m = 3/4

c = (-8)

Therefore, you can simply put 3/4 and (-8) instead of m and c respectively like this.

y = m x + c

y = 3/4x - 8

Hope this helps you.

Let me know if you have any other questions :-)

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