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3 years ago

What is the slope of line a? • -4 • 4 • -1/4 • 1/4

Mathematics

2 answers:

Shtirlitz [24]3 years ago

6 0

I think it’s four. If not then I’m sorry

quester [9]3 years ago

3 0

Answer:

-1/4 is the correct answer

Step-by-step explanation:

you’re going down 1 and over 4 :)

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Find the digit that makes 3,71_divisible by 9. A.3 B.7 C.1 D.5

ipn [44]

Answer:the answer is d

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Select the correct answer.

zhannawk [14.2K]

You have a good day and good luck on that question

8 0

3 years ago

Evaluate your expression for m =12

Feliz [49]

There's no way for me to do that, because my expression
is totally blank, and doesn't involve ' m ' in any way.

But if you'll come back and give us your expression, I'll
evaluate it for m=12, and I'll also show you how.

3 0

3 years ago

In a certain communications system, there is an average of 1 transmission error per 10 seconds. Assume that the distribution of

Nitella [24]

Answer:

The probability of 1 error in a period of 0ne - half minute is 0.1494

Step-by-step explanation:

Formula for poisson distribution:

$P (X = k) = \frac{\exp^{- \lambda} \lambda^{x} }{x!}$

If there is an average of 1 error in 10 seconds

In one-half minutes (i.e. 30 seconds), there will be an average of 30/10 errors = 3 errors

$\lambda = 3 errors\\x = 1$

$P (X = 1) = \frac{\exp^{-3} 3^{1} }{1!}$

1! = 1

$P (X = 1) = 3 \exp^{-3}$

P(X = 1) = 3 * 0.0498

P(X = 1) = 0.01494

7 0

3 years ago

Read 2 more answers

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$

we get:

$V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}$

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

4 0

3 years ago